Working simultaneously and independently at an identical constant rate

Question

Working simultaneously and independently at an identical constant rate, 4 machines of a
certain type can produce a total of x units of product P in 6 days. How many of these
machines, working simultaneously and independently at this constant rate, can produce a
total of 3x units of product P in 4 days?
A. 24
B. 18
C. 16
D. 12
E. 8

A. 24
B. 18
C. 16
D. 12
E. 8

Bunuel · Accepted Answer

Working simultaneously and independently at an identical constant rate, 4 machines of a
certain type can produce a total of x units of product P in 6 days. How many of these
machines, working simultaneously and independently at this constant rate, can produce a
total of 3x units of product P in 4 days?
A. 24
B. 18
C. 16
D. 12
E. 8

(A) 24
(B) 18
(C) 16
(D) 12
(E) 8

The rate of 4 machines is rate=job/time=x/6 units per day --> the rate of 1 machine 1/4*(x/6)=x/24 units per day;

Now, again as {time}*{combined rate}={job done} then 4*(m*x/24)=3x --> m=18.

Or as 3 times more job should be done in 1.5 times less days than 3*1.5=4.5 times more machines will be needed 4*4.5=18.

Answer: B.

bhaskar438 · Answer

If it takes 4 machines 6 days to produce x units
then it takes 4 machines 18 days to produce 3x units
then it takes  M  machines 4 days to produce 3x units

There is an inverse relationship between the amount of time and the number of machines required to do the task 
 So if the task is 3x units, then (4 machines)*(18 days)=(M machines)*(4 days) --> M = 18

Correct answer choice is  B.

mailnavin1 · Answer

4 machines and 6 days so the total work done is 24

4x6=24
now 3 times the work is 72

So in 4 days if the work is to be completed its 72/4 = 18

KarishmaB · Answer

Using the method discussed in this post: https://anaprep.com/arithmetic-work-rat ... variation/ 4 machines --- x units --- 6 days ? machines --- 3x units -- 4 days Machines required = 4 * (3x/x) * (6/4) = 18 Answer (B)

v12345 · Answer

we have x units by 4 machine in 6 days

=> x units in 24 machine days
=> 3x units in 72 machine days

therefore machine required = 72 / 4 = 18

Answer choice B

JeffTargetTestPrep · Answer

We are given that 4 machines can produce a total of x units in 6 days. Since rate = work/time, the rate of the 4 machines is x/6. We need to determine how many machines, working at the same rate, can produce 3x units of product P in 4 days. Thus, we need to determine how many machines are needed for a rate of 3x/4.

Since we know that all the machines are working at an identical constant rate, we can create a proportion to determine the number of machines necessary for a rate of 3x/4. The proportion is as follows:

“4 machines are to a rate of x/6 as n machines are to a rate of 3x/4."

4/(x/6) = n/(3x/4)

24/x = 4n/(3x)

When we cross multiply, we obtain:

72x = 4xn

18 = n

Answer: B

bhavinshah5685 · Answer

Rate*Time = Work
(4R)*(6)=x ( Total 4 machines)
therefore R=x/24

now again (n)*(x/24)*(4) = 3x

solving for n, we get n=18 nos.

EvaJager · Answer

4 machines----------x units-----------6days
4 machines---------3x units-----------3*6 = 18 days
M machines---------3x unites----------4 days
The number of days and the number of machines which produce a certain number of units (in this case 3x) are inversely proportional.
This is because all the machines have the same constant rate.
Necessarily 4*18=M*4, therefore M = 18.

Answer B

GMATPill · Answer

This is a variation of the Distance = Rate * Time

Except we modify and say Output = # Machines * (Rate * Time)

X = # * r*t

X = 4 * r * 6
x = 24r
r = x/24

Solve for r because we want to find out the rate...then apply that rate to the new situation, which is output of 3x in 4 days

3x = N * r * 4

3x = N * (x/24) * 4
3x = N * (x/6)

18x = N *x
18 = N

ske · Answer

solving in shortcut m1 d1 h1 / w1 = m2 d2 h2/w2 4x6/x = mx4/3x solving we get m=18 answer b press kudos if you love my shortcut :-D

mvictor · Answer

Working simultaneously and independently at an identical constant rate, 4 machines of a
certain type can produce a total of x units of product P in 6 days. How many of these
machines, working simultaneously and independently at this constant rate, can produce a
total of 3x units of product P in 4 days?
A. 24
B. 18
C. 16
D. 12
E. 8

tough one, let's see...
4 machines do x units in 6 days

we have x/6 => rate of the 4 machines

we know that we need to have 3x units in 4 days
therefore, we need to get to 3x/4 rate of the machines.

rate of one machine is x/6*1/4 = x/24.

now, we need to know how many machines need to work simultaneously, to get 3x done in 4 days.
4x/4 work needs to be done by machines that work at x/24 rate.

let's assign a constant Y for the number of machines:
(x/24)*y = 3x/4

y = 3x/4 * 24/x
cancel 4 with 24, and x with x and get -> 18. Answer choice B

Skywalker18 · Answer

Let work done per machine per day = m

Work done by 4 machines in a day, 4m = x/6 
Work done by 1 machine in a day , m = x/24

Since work needs to completed in 4 days , work done by 1 machine in 4 days = x/6
Number of machines required = Total work to be completed in 3 days/ Work done by a single machine in 4 days 
 = 3x/(x/6) = 18
 
Answer B

KarishmaB · Answer

Forget "work" here - whether it is more or less. Focus on the relation between the unknown and the variable in question only. So focus on machines and days only.

You have fewer days so you will need more machines to complete the work. So you multiply by 6/4, a quantity greater than 1. This will increase the number of machines.

Dienekes · Answer

4 machines take 6 days to complete x amount of work, so 1 machine will take  6*4=24  days to complete same work. 3x, i.e. three times of work will require that single machine to work for  24*3=72  days. Now in order to do 72 days worth of work in 4 days, we'd need  72/4=18  machines.
Answer: B

swatikshar15 · Answer

4 machines can do x work in 6 days
4 machines can do x/6 work in 1 day
1 machine can do x/6*1/4 work in 1 day

so,

n machines in 4 days= 3x work
n machines in 1 day = n * (x/6*1/4)
n machines in 4 days = n * (x/6*1/4)*4

Hence, n machines can do n*(x/6*1/4)*4 work in 4 days i.e. n*(x/6*1/4)*4 =3x ====>>>> n=18

glt13 · Answer

given : 4 machines rate = x stuff / 6 days or 4m = x/6

need to find y machines = 3x stuff / 4 days = ym = 3x/4

two equations, two unknowns, solvable now.

4 = x/6 & y = 3x/4
4 = x/6 
24 = x (now plug into second equation)

y = 3(24) / 4
y = 3(6)
y = 18

mcelroytutoring · Answer

Attached is a visual that should help.

ashutoshsh · Answer

Let individual rate be 'a'
therefore, for 4 machines we have:
 \frac{1}{a} +\frac{1}{a} + \frac{1}{a} +\frac{1}{a} = \frac{x}{6} 
--> \frac{4}{a} = \frac{x}{6} 
--> ax = 6 x 4 = 24 ......(eq1)
now If Z machines of same rate were used to produce 3x work in 4 days, we would have:
Z( \frac{1}{a} ) =  \frac{3x}{4} 
--> Z =  \frac{3x(a)}{4} 
--> Z =  \frac{3 (24)}{4}  ......(using eq1)
--> Z = 18

GMATAcademy · Answer

Here's a way to solve this question quickly:

https://www.youtube.com/watch?v=mGe17Ty_lvQ

Here's a more in-depth look at a reliable approach for combined work questions with multiple identical machines:

https://www.youtube.com/watch?v=XOtwd6brDj8

Working simultaneously and independently at an identical constant rate

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Working simultaneously and independently at an identical constant rate

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

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