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Working simultaneously and independently at an identical constant rate

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Intern
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Joined: 15 Oct 2017
Posts: 15
Working simultaneously and independently at an identical constant rate [#permalink]

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New post 02 Jan 2018, 22:08
Hi guys,

It's always tricky for me to answer this kind of question. I tried Bunuel's method, but somehow I found VeritasPrepKarishma 's method easier. I hope what I posted below is correct. :-)
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Intern
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Joined: 23 Jan 2018
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Re: Working simultaneously and independently at an identical constant rate [#permalink]

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New post 08 Feb 2018, 07:32
Hello,

I follow a very simple approach that is shown to us in the Gmat Club Math Book.

Let d = number of days; n = number of machines

So, firstly, we get this expression from what is said in the exercise:

(x/d)*4=(x/6)

But since we know 1 job done is equivalent to x, in this case, we can represent it as the following:

(1/d)*4=(1/6) which gives us d=24 days

Thus: (1/24)*n=(3/4) ,which gives us n=18
Re: Working simultaneously and independently at an identical constant rate   [#permalink] 08 Feb 2018, 07:32

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