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For every positive integer n that is greater than 1, the function g(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The g(n) could have any of the following units digits except…?

Used brute force on this one to calculate. Not sure if there is a quicker way.

1+3=4 C is out
1+3+....15= 81 A is out
1+3+5+7=16 D is out
1+3+5=9 E i out

Answer: B
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EMPOWERgmatRichC
QUANT 4-PACK SERIES Problem Solving Pack 4 Question 2 For every positive integer n...

For every positive integer n that is greater than 1, the function g(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The g(n) could have any of the following units digits except…?

A) 1
B) 2
C) 4
D) 6
E) 9

Hi All,

GMAT Quant questions are built around patterns - whether you immediately spot (or know) the pattern or not. As such, even if you don't know the exact patterns involved, you can often PROVE what the pattern is by TESTing VALUES and doing some basic arithmetic.

Here, we're told that n is a positive integer greater than 1 and that the function g(n) is defined to be the sum of all of the ODD integers from 1 to n, inclusive. We're asked to find the digit that CAN'T be the unit's digit of any potential calculation that could be done using this function.

Rather than stare at the screen or do math in our heads, let's TEST VALUES and seek out the pattern.

Since n is GREATER than 1, let's start with 2...

g(2) = 1
So the unit's digit COULD be 1.
Eliminate Answer A.

g(3) = 1 + 3 = 4
So the unit's digit COULD be 4.
Eliminate Answer C.

g(5) = 1 + 3 + 5 = 9
So the unit's digit COULD be 9.
Eliminate Answer E.

g(7) = 1 + 3 + 5 + 7 = 16
So the unit's digit COULD be 6.
Eliminate Answer D.

With 4 answers eliminated, there's just one answer left...

Final Answer:
GMAT assassins aren't born, they're made,
Rich
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QUANT 4-PACK SERIES Problem Solving Pack 4 Question 2 For every positive integer n...

For every positive integer n that is greater than 1, the function g(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The g(n) could have any of the following units digits except…?

A) 1
B) 2
C) 4
D) 6
E) 9


48 Hour Window Answer & Explanation Window
Earn KUDOS! Post your answer and explanation.
OA, and explanation will be posted after the 48 hour window closes.

This question is part of the Quant 4-Pack series

Scroll Down For Official Explanation

Sum of the first n positive integers upto n is given by

\(n^2\)

now these can be either even number of odd numbers or odd number of odd numbers.

Thus the question is "Which of the following cannot be the units digit of a perfect square".

Answer (B). :)
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QUANT 4-PACK SERIES Problem Solving Pack 4 Question 2 For every positive integer n...

For every positive integer n that is greater than 1, the function g(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The g(n) could have any of the following units digits except…?

A) 1
B) 2
C) 4
D) 6
E) 9

1+3 = 4 -> C is out
4+5 = 9 -> E is out
9+7 = 16 -> D is out
16+9 = 25.
25+11 = 36
36+13 = 49
49+15 = 64
64+17 = 81 - A is out

only left - B!
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For every positive integer n that is greater than 1, the function g(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The g(n) could have any of the following units digits except…?

A) 1
B) 2
C) 4
D) 6
E) 9

\(\\
No need of even a single calculation
\)

Function \(g(n) =\) \(n^2\) { Sum of odd integers }

Since \(n^2\) is a square number it must end in 1 , 2 , 4 , 6 , 9 and 0


Since Units digit of \(n^2\) can not be 2, our answer will be (B)
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the sum of the odd integers from 1 to n --> g(n) --> is equal to n^2
we have to check if there are perfect squares that end in one of the digits provided.
thus, by checking the values of n^2, we can conclude that 2 is the only digit that cannot be unit digit


EMPOWERgmatRichC
QUANT 4-PACK SERIES Problem Solving Pack 4 Question 2 For every positive integer n...

For every positive integer n that is greater than 1, the function g(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The g(n) could have any of the following units digits except...?

A) 1
B) 2
C) 4
D) 6
E) 9


48 Hour Window Answer & Explanation Window
Earn KUDOS! Post your answer and explanation.
OA, and explanation will be posted after the 48 hour window closes.

This question is part of the Quant 4-Pack series

Scroll Down For Official Explanation
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For every positive integer n that is greater than 1, the function g(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The g(n) could have any of the following units digits except...?

A) 1
B) 2
C) 4
D) 6
E) 9

The sum of odd integers is defined by n^2.

Looking at the rest of the options we can deduce it is B because 2 CANNOT wound up as the unit digit of absolutely any square, as opposed to the rest of the options.
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