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Bunuel
If the numerator of a fraction is tripled, and the denominator of a fraction is doubled, the resulting fraction will reflect an increase of what percent?

A. 16 1⁄6%
B. 25%
C. 33 1⁄3%
D. 50%
E. 66 2⁄3%

fraction = x / y

New Fraction = 3x / 2y = 1.5(x/y)

i.e. Increase = [1.5(x/y) - (x/y)]*100/(x/y) = 50%

Answer: option D
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Bunuel
If the numerator of a fraction is tripled, and the denominator of a fraction is doubled, the resulting fraction will reflect an increase of what percent?

A. 16 1⁄6%
B. 25%
C. 33 1⁄3%
D. 50%
E. 66 2⁄3%

There can be two methods to solve this problem:

1. Plain old method of assuming the variables.
Assume original fraction = \(\frac{x}{y}\)
Fraction after changes = \(\frac{3x}{2y}\)

%age increase = (new - old)/old * 100 = (3x/2y - x/y ) / (x/y)* 100 =(x/2y) / (x/y)*100 = 1/2*100
= 50 % (Option D)
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Bunuel
If the numerator of a fraction is tripled, and the denominator of a fraction is doubled, the resulting fraction will reflect an increase of what percent?

A. 16 1⁄6%
B. 25%
C. 33 1⁄3%
D. 50%
E. 66 2⁄3%

We can let the numerator = n and the denominator = d, and we have n/d.

Since the numerator of a fraction is tripled and the denominator of a fraction is doubled, we have:

3n/2d

Let’s determine the percentage increase:

(3n/2d - n/d)/n/d x 100

(3n/2d - 2n/2d)/n/d x 100

(n/2d)/n/d x 100

dn/2dn x 100 = 1/2 x 100 = 50%

Answer: D
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here we need to understand the stem clearly as the only case when the increase could happen when numerator is > denominator
take 3/2 now triple 3 and double 2 = 9/4

we can easily calculate the % increase = 9-6/4= 100/2= 50%

hence D
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IMO D 50%
initial ratio x/y
after changes 3x/2y or 1.5xy that means increase of 50 percent .
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