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14 Feb 2016, 05:40
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Difficulty:
35%
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Question Stats:
73% (02:20) correct
27%
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Set A contains all the even numbers between 2 and 50 inclusive. Set B contains all the even numbers between 102 and 150 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A?
A. 2500
B. 2550
C. 5050
D. 6275
E. 11325
A. 2500
B. 2550
C. 5050
D. 6275
E. 11325
14 Feb 2016, 12:35
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Set A contains 2,4 , 6 ... 50
Set B contains 102 , 104 , 106 ... 150
Number of terms in each set = 25
Difference between corresponding terms in set A and B = 100
Difference between Sum of set B and set A = 100*25 = 2500
Answer A
Set B contains 102 , 104 , 106 ... 150
Number of terms in each set = 25
Difference between corresponding terms in set A and B = 100
Difference between Sum of set B and set A = 100*25 = 2500
Answer A
22 Jun 2017, 19:41
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The sum of even numbers between 2 and 50 (inclusive) through average is equal the average of numbers times the number of elements
\(\frac{50+2}{2} * \frac{50-2}{2} +1\)
The same with the sum between 102 and 150
\(\frac{150+102}{2} * \frac{150-102}{2}+1\)
Therefore, we have: the difference of the lager sum and the smaller sum
\((126 * 25) - (26*25) = 25* (126-26) = 25*100= 2500\)
\(\frac{50+2}{2} * \frac{50-2}{2} +1\)
The same with the sum between 102 and 150
\(\frac{150+102}{2} * \frac{150-102}{2}+1\)
Therefore, we have: the difference of the lager sum and the smaller sum
\((126 * 25) - (26*25) = 25* (126-26) = 25*100= 2500\)
