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Bunuel
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Which of the following could be p if |3p – 4| < 1? 25 Dec 2016, 02:35
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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25% (medium)

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74% (01:12) correct 26% (01:09) wrong based on 580 sessions

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Which of the following could be p if |3p – 4| < 1?

A. 1/4
B. 5/4
C. 5/3
D. 0
E. 2
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B
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Which of the following could be p if |3p – 4| < 1? 25 Dec 2016, 02:45
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|3p-4| <1
=-1< 3p-4 <1
= 3<3p<5
= 1< P<5/3

So ans is (B) which satisfies the above equation

Sent from my Redmi Note 3 using GMAT Club Forum mobile app
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Which of the following could be p if |3p – 4| < 1? 15 Jan 2018, 09:48
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Bunuel
Which of the following could be p if |3p – 4| < 1?

A. 1/4
B. 5/4
C. 5/3
D. 0
E. 2
Show more
No need to solve this question , just plug in and check ( 10 sec) answer will definitely be (B)

\(\frac{3*5}{4} - 4\)

= \(\frac{1}{4}\), answer will be clearly (B)
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Which of the following could be p if |3p – 4| < 1? 05 Mar 2018, 09:37
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Can someone please, explain my mistake:

Which of the following could be p if |3p – 4| < 1?

A. 1/4 B. 5/4 C. 5/3 D. 0 E. 2

a. |3p – 4| < 1; 3p < 1 + 4; p <5/3

b. |3p – 4| < 1; 3p <-1 + 4; p < 3/3; p < 1

I selected 1/4, being more restricitive.
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Which of the following could be p if |3p – 4| < 1? 05 Mar 2018, 21:13
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hero_with_1000_faces
Can someone please, explain my mistake:

Which of the following could be p if |3p – 4| < 1?

A. 1/4 B. 5/4 C. 5/3 D. 0 E. 2

a. |3p – 4| < 1; 3p < 1 + 4; p <5/3

b. |3p – 4| < 1; 3p <-1 + 4; p < 3/3; p < 1

I selected 1/4, being more restricitive.
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Highlighted part is incorrect.

If you open brackets with a < sign. . .

Case 1: absolute value < RHS
3P - 4 < 1
3P < 5
P < \(\frac{5}{3}\)

Case 2: absolute value > -RHS
3P - 4 > -1
3P > 3
P > 1

and
P < \(\frac{5}{3}\)

1 < P < \(\frac{5}{3}\)

P has to fall between 1 and \(\frac{5}{3}\)

Only \(\frac{5}{4}\) does that.

0 and \(\frac{1}{4}\) are too small.

\(\frac{5}{3}\) and 2 are too great.

Easy mistake to make in the arithmetic. :-) Hope that helps
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Which of the following could be p if |3p – 4| < 1? 05 Mar 2018, 23:33
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generis Thank you for your kind explanation. I have read Manhattan, gone through magoosh videos and still had a flawed understanding. Thank You.




generis
hero_with_1000_faces
Can someone please, explain my mistake:

Which of the following could be p if |3p – 4| < 1?

A. 1/4 B. 5/4 C. 5/3 D. 0 E. 2

a. |3p – 4| < 1; 3p < 1 + 4; p <5/3

b. |3p – 4| < 1; 3p <-1 + 4; p < 3/3; p < 1

I selected 1/4, being more restricitive.
Highlighted part is incorrect.

If you open brackets with a < sign. . .

Case 1: absolute value < RHS
3P - 4 < 1
3P < 5
P < \(\frac{5}{3}\)

Case 2: absolute value > -RHS
3P - 4 > -1
3P > 3
P > 1

and
P < \(\frac{5}{3}\)

1 < P < \(\frac{5}{3}\)

P has to fall between 1 and \(\frac{5}{3}\)

Only \(\frac{5}{4}\) does that.

0 and \(\frac{1}{4}\) are too small.

\(\frac{5}{3}\) and 2 are too great.

Easy mistake to make in the arithmetic. :-) Hope that helps
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Which of the following could be p if |3p – 4| < 1? 08 Mar 2018, 11:39
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Bunuel
Which of the following could be p if |3p – 4| < 1?

A. 1/4
B. 5/4
C. 5/3
D. 0
E. 2
Show more

Scanning our answer choices, we see that answer choice B is correct.

|3(5/4) - 4| < 1

|15/4 - 4| < 1

|15/4 - 16/4| < 1

|-1/4| < 1

1/4 < 1

Alternate Solution:

In order for the absolute value of an expression to be less than 1, the value of the expression itself must be between -1 and 1; in other words, we must have:

-1 < 3p - 4 < 1

3 < 3p < 5

1 < p < 5/3

5/4 is the only value amongst the answer choices that is included in this interval.

Answer: B
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Which of the following could be p if |3p – 4| < 1? 05 Jul 2024, 02:34
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