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06 Feb 2017, 07:26
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Difficulty:
45%
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Question Stats:
67% (01:51) correct
33%
(02:04)
wrong
based on 634
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Set A is a set of 25 distinct multiples of 3 and Set B is a set of 40 distinct multiples of 2. There are 5 distinct multiples of 6 which appear in both sets A and B. If C is the set of numbers belonging to sets A and B but not both, how many integers are in set C?
A. 5
B. 30
C. 55
D. 60
E. 70
A. 5
B. 30
C. 55
D. 60
E. 70
06 Feb 2017, 07:58
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Ans- C, 55
As asked only in set A and B, which is 25-5(common)=20 and 40-5(common)=35.
Set C comprise of only A and B i.e. 20+35=55
As asked only in set A and B, which is 25-5(common)=20 and 40-5(common)=35.
Set C comprise of only A and B i.e. 20+35=55
06 Feb 2017, 08:51
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Bunuel
A = set of 25 distinct multiples of 3
B = set of 40 distinct multiples of 2
Number in Set C from Set A = 25 (Total Numbers in A) - 5 (common numbers) = 20
Number in Set C from Set B = 40 (Total Numbers in A) - 5 (common numbers) = 35
Total Members in Set C = 20+35 = 55
Answer: Option C
