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Bunuel
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Bunuel
Three machines are operating simultaneously and independently at different rates. Machine A produces 1 widget in 4 minutes, Machine B produces 1 widget in 3 minutes, and Machine C produces 1 widget in 5 minutes. If two machines are to be chosen to make 20 widgets in the shortest possible time, approximately how many minutes will it take to produce 20 widgets?

A. 30
B. 34
C. 36
D. 44
E. 70


..........R.......T......W
A.......1/4.....
B.......1/3
C.......1/5
A+B...7/12...x.....20


T= W/R
T=20/(7/12)
(20*12)/7 = 34.2

Answer : B
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My approach

1/4 + 1/3 = 7/12

7/12 x = 20
x = 34

Answer is B
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Hi Bunuel,

I have one question, It is given in the question that, Machines work simultaneouly but independently.
So can machines share work to produce single widget?

Option B - 34 mins, by 33 mins, Machine A would have produced 8 widgets, Machine B would have produced 11 widgets, now the machines A and B must share producing the last widget to finish by 34 mins approx.

If machines cannot share producing, then answer must be 36 mins..right?

Because, there is similiar problem https://gmatclub.com/forum/crew-a-can-b ... 92819.html
in which, there two crews producing cars, but crews work independently and simulatenously

Can you please help.
thanks
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Always convert everything in terms of rates -
A - 1/4; b = 1/3; C = 1/5
Fastest two - A and B

Overall rate of A and B combined =1/3+1/4 = 7/12 widgets/minutes

So, 7 widgets take 12 mins -
1 widget will take 12/7 mins
so 20 widgets will take - 12/7*20 = 34(approx)
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