Last visit was: 21 Apr 2026, 19:07 It is currently 21 Apr 2026, 19:07
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
555-605 (Medium)|   Arithmetic|                     
User avatar
Carcass
User avatar
Board of Directors
Joined: 01 Sep 2010
Last visit: 20 Apr 2026
Posts: 4,711
Own Kudos:
37,829
 [79]
Given Kudos: 4,925
Posts: 4,711
Kudos: 37,829
 [79]
7
Kudos
Add Kudos
71
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 21 Apr 2026
Posts: 109,728
Own Kudos:
Given Kudos: 105,800
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,728
Kudos: 810,475
 [15]
8
Kudos
Add Kudos
5
Bookmarks
Bookmark this Post
User avatar
generis
User avatar
Senior SC Moderator
Joined: 22 May 2016
Last visit: 18 Jun 2022
Posts: 5,258
Own Kudos:
37,724
 [7]
Given Kudos: 9,464
Expert
Expert reply
Posts: 5,258
Kudos: 37,724
 [7]
5
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
General Discussion
User avatar
exc4libur
Joined: 24 Nov 2016
Last visit: 22 Mar 2022
Posts: 1,680
Own Kudos:
Given Kudos: 607
Location: United States
Posts: 1,680
Kudos: 1,469
Kudos
Add Kudos
Bookmarks
Bookmark this Post
carcass
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing 16 \(\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?

A. 50

B. 64

C. 67

D. 768

E. 804

I. 12 packs containing 16.75 lbs each: Total = 12*16.75 lbs
II. Total/(1/4) = Total*4 = (12*16.75)*4 = [12*16+12*3/4]*4 = [201]*4 = 804 bags
User avatar
tapasgupta
Joined: 10 Mar 2016
Last visit: 20 May 2023
Posts: 115
Own Kudos:
Given Kudos: 22
Location: India
Concentration: Finance, Real Estate
GMAT 1: 550 Q44 V23
WE:Corporate Finance (Commercial Banking)
Products:
GMAT 1: 550 Q44 V23
Posts: 115
Kudos: 243
Kudos
Add Kudos
Bookmarks
Bookmark this Post
option E
3/4 part of the 16 will give 3 bags.
1 pound will give 4.
Total is 16. So 16*4+3=67
Now 67 *12= 804 bags
User avatar
TimeTraveller
Joined: 28 Jun 2015
Last visit: 29 Jul 2017
Posts: 237
Own Kudos:
Given Kudos: 47
Concentration: Finance
GPA: 3.5
Posts: 237
Kudos: 360
Kudos
Add Kudos
Bookmarks
Bookmark this Post
\(12 * (\frac{3}{4} * 4 + 16 * 4) = 12 * (3+64) = 804\). Ans - E.
User avatar
rulingbear
Joined: 03 May 2017
Last visit: 03 Oct 2018
Posts: 57
Own Kudos:
Given Kudos: 15
Posts: 57
Kudos: 58
Kudos
Add Kudos
Bookmarks
Bookmark this Post
carcass
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804

I would do 67/4 * 12* 4= 201*4= 804, E.
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 21 Apr 2026
Posts: 22,276
Own Kudos:
26,526
 [3]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,276
Kudos: 26,526
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
carcass
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804

The total fruit purchased, in pounds, was:

12 x 16 ¾ = 12 x 67/4 = 3 x 67 = 201

Thus, the number of bags of fruit, each containing 1/4 pounds, that can be sold is:

201/(1/4) = 201 x 4 = 804

Answer: E
User avatar
loserunderachiever
Joined: 26 Feb 2018
Last visit: 14 Aug 2018
Posts: 36
Own Kudos:
8
 [1]
Given Kudos: 24
WE:Sales (Internet and New Media)
Posts: 36
Kudos: 8
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
QA E ,
12*67/4 = 804/4/1/4 = 804
User avatar
jalice
Joined: 16 May 2017
Last visit: 14 May 2023
Posts: 39
Own Kudos:
Given Kudos: 78
GPA: 3.8
WE:Medicine and Health (Healthcare/Pharmaceuticals)
Posts: 39
Kudos: 19
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let the maximum number of individual bags of dried fruit, each containing 1/4 pounds be "B"
1/4*B=67/4*12 (as total weight of dried fruits=67/4*12 pounds)
B=804

Answer (E)
User avatar
hasnain3047
Joined: 20 Jul 2018
Last visit: 05 Sep 2018
Posts: 67
Own Kudos:
Given Kudos: 19
GPA: 2.87
Posts: 67
Kudos: 98
Kudos
Add Kudos
Bookmarks
Bookmark this Post
1 container weight = 67/4 pounds
12 containers weight = 67*12/4 = 201 pounds
Number of packges that can be made of 1/4 pounds = 201/(1/4) = 201*4 = 804

Posted from my mobile device
User avatar
Salsanousi
Joined: 19 Oct 2013
Last visit: 29 Dec 2020
Posts: 391
Own Kudos:
358
 [1]
Given Kudos: 117
Location: Kuwait
GPA: 3.2
WE:Engineering (Real Estate)
Posts: 391
Kudos: 358
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
carcass
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804

\(16\frac{3}{4}\) = \(\frac{67}{4}\) and \(\frac{67}{4}* 12 = 201\)

Basically 1 pound makes 4 bags (because bag takes \(\frac{1}{4}\) pounds)

Multiply 201 by 4 = 804

Answer choice E
User avatar
Probus
Joined: 10 Apr 2018
Last visit: 22 May 2020
Posts: 178
Own Kudos:
Given Kudos: 115
Location: United States (NC)
Posts: 178
Kudos: 561
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi, we can solve this alternatively

if we assume that each lot contains 17 pounds.

Then total we have is 17 *12.

We need to distribute them in bags which can hold upto 1/4 pounds.

the total number of bags in this case would be 17*12*4= 816

Since we have taken 1/4 more than given lot size , the additional bags because of these 1/4 is = 1/4*12*4 = 12

So total number of bags are 816-12= 804


Hope this helps
User avatar
gmatway
Joined: 01 Dec 2018
Last visit: 05 Dec 2020
Posts: 140
Own Kudos:
Given Kudos: 333
Concentration: Entrepreneurship, Finance
Schools: HBS '21 ISB'22
GPA: 4
WE:Other (Retail Banking)
Schools: HBS '21 ISB'22
Posts: 140
Kudos: 163
Kudos
Add Kudos
Bookmarks
Bookmark this Post
carcass
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804

I think the most logical and easiest approach is

16 3/4 = 16.75 (as 1/4 = .25 so 3/4 = .75)
12 * 16.75 (i.e total bags *dry fruits in 1 bag = total dry fruits ) = 201

step 2
now I have total dry fruits 201 and a pouch should have 1/4 dry fruits so how many such bags would be there
201 = 1/4 * x (where X is total no. of pouch with 1/4 dry fruits in each pouch ) => 804 ans E
User avatar
MHIKER
Joined: 14 Jul 2010
Last visit: 24 May 2021
Posts: 939
Own Kudos:
Given Kudos: 690
Status:No dream is too large, no dreamer is too small
Concentration: Accounting
Posts: 939
Kudos: 5,810
Kudos
Add Kudos
Bookmarks
Bookmark this Post
carcass
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804

I did altogether in a raw:
12x(67/4)x4/1 = 67x 12= 804
Ans E.
User avatar
Basshead
Joined: 09 Jan 2020
Last visit: 07 Feb 2024
Posts: 907
Own Kudos:
Given Kudos: 431
Location: United States
Posts: 907
Kudos: 323
Kudos
Add Kudos
Bookmarks
Bookmark this Post
16 3/4 = 67/4

67/4 * 12 = 201

201 * 4 = 804

Answer is E.
User avatar
plaverbach
User avatar
Retired Moderator
Joined: 25 Mar 2014
Last visit: 28 Sep 2021
Posts: 212
Own Kudos:
Given Kudos: 250
Status:Studying for the GMAT
Location: Brazil
Concentration: Technology, General Management
GMAT 1: 700 Q47 V40
GMAT 2: 740 Q49 V41 (Online)
WE:Business Development (Finance: Venture Capital)
Products:
GMAT 2: 740 Q49 V41 (Online)
Posts: 212
Kudos: 540
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Quick way (!)
The result must be divisible by 12, therefore, by 3. E is the only divisible by 3
User avatar
ThatDudeKnows
Joined: 11 May 2022
Last visit: 27 Jun 2024
Posts: 1,070
Own Kudos:
Given Kudos: 79
Expert
Expert reply
Posts: 1,070
Kudos: 1,030
Kudos
Add Kudos
Bookmarks
Bookmark this Post
carcass
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?

A. 50
B. 64
C. 67
D. 768
E. 804
Probus
Hi, we can solve this alternatively

if we assume that each lot contains 17 pounds.

Then total we have is 17 *12.

We need to distribute them in bags which can hold upto 1/4 pounds.

the total number of bags in this case would be 17*12*4= 816

Since we have taken 1/4 more than given lot size , the additional bags because of these 1/4 is = 1/4*12*4 = 12

So total number of bags are 816-12= 804


Hope this helps


You and I are on the same page, Probus. Why would I work with 64/7 unless absolutely necessary?!?

One little tweak for me. I don't like 17. It's just not a number that feels great for me to work with. So, I went with 16. Since I've rounded down, I'll put a little (+) next to each step in my calculations to remind me that I need an answer choice that's a little bigger than what I've got.

16*12 = 160+32 = 192(+)
Now I need to multiply that by 4, so 192*4, which is 768(+).

There's only one answer choice that's a little bigger than the 768 I got.

Answer choice E.

ThatDudeKnowsBallparking
User avatar
Gaurav07
Joined: 15 May 2021
Last visit: 20 Apr 2026
Posts: 54
Own Kudos:
Given Kudos: 61
Location: India
Schools: Smith (A)
GPA: 4
Products:
Schools: Smith (A)
Posts: 54
Kudos: 4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

carcass
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804
12 containers of dried fruit, each containing \(16\frac{3}{4}=\frac{67}{4}\) pounds = \(\frac{12*67}{4}\) pounds.

\(\frac{(\frac{12*67}{4})}{(\frac{1}{4})}=\frac{12*67}{4}*4=12*67=...4\) (something with units digit of 4 but for sure greater than 64, gives only E).

Answer; E.
­Great explanation Brunel! Can you please help with similar questions like this for practice?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 21 Apr 2026
Posts: 109,728
Own Kudos:
Given Kudos: 105,800
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,728
Kudos: 810,475
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Gaurav07

Bunuel

carcass
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804
12 containers of dried fruit, each containing \(16\frac{3}{4}=\frac{67}{4}\) pounds = \(\frac{12*67}{4}\) pounds.

\(\frac{(\frac{12*67}{4})}{(\frac{1}{4})}=\frac{12*67}{4}*4=12*67=...4\) (something with units digit of 4 but for sure greater than 64, gives only E).

Answer; E.
­Great explanation Brunel! Can you please help with similar questions like this for practice?
­
This is an arithmetic problem, so you can check the questions listed under that tag:

https://gmatclub.com/forum/search.php?s ... &tag_id=51

Hope this helps.
 1   2   
Moderators:
Math Expert
109728 posts
Tuck School Moderator
853 posts