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A school club plans to package and sell dried fruit to raise money. Th
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23 Jul 2017, 10:50
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A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ? A. 50 B. 64 C. 67 D. 768 E. 804
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Re: A school club plans to package and sell dried fruit to raise money. Th
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23 Jul 2017, 15:35
carcass wrote: A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing 16 \(\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?
A. 50
B. 64
C. 67
D. 768
E. 804 Total pounds of dried fruit: 12 containers * 16\(\frac{3}{4}\) lbs / container = (12*16) + (12*\(\frac{3}{4}\)) = (192 + 9) = 201 pounds How many quarterpound bags can be made from 201 total pounds? \(\frac{201}{(\frac{1}{4})\) = 201 * 4 = 804 Answer E
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Re: A school club plans to package and sell dried fruit to raise money. Th
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23 Jul 2017, 15:49
carcass wrote: A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing 16 \(\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?
A. 50
B. 64
C. 67
D. 768
E. 804 I. 12 packs containing 16.75 lbs each: Total = 12*16.75 lbs II. Total/(1/4) = Total*4 = (12*16.75)*4 = [12*16+12*3/4]*4 = [201]*4 = 804 bags



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Re: A school club plans to package and sell dried fruit to raise money. Th
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24 Jul 2017, 00:37
carcass wrote: A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?
A. 50
B. 64
C. 67
D. 768
E. 804 12 containers of dried fruit, each containing \(16\frac{3}{4}=\frac{67}{4}\) pounds = \(\frac{12*67}{4}\) pounds. \(\frac{(\frac{12*67}{4})}{(\frac{1}{4})}=\frac{12*67}{4}*4=12*67=...4\) (something with units digit of 4 but for sure greater than 64, gives only E). Answer; E.
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Re: A school club plans to package and sell dried fruit to raise money. Th
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24 Jul 2017, 10:35
option E 3/4 part of the 16 will give 3 bags. 1 pound will give 4. Total is 16. So 16*4+3=67 Now 67 *12= 804 bags
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Re: A school club plans to package and sell dried fruit to raise money. Th
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24 Jul 2017, 10:41
\(12 * (\frac{3}{4} * 4 + 16 * 4) = 12 * (3+64) = 804\). Ans  E.
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Re: A school club plans to package and sell dried fruit to raise money. Th
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24 Jul 2017, 10:54
carcass wrote: A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?
A. 50
B. 64
C. 67
D. 768
E. 804 I would do 67/4 * 12* 4= 201*4= 804, E.



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Re: A school club plans to package and sell dried fruit to raise money. Th
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26 Jul 2017, 16:17
carcass wrote: A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?
A. 50
B. 64
C. 67
D. 768
E. 804 The total fruit purchased, in pounds, was: 12 x 16 ¾ = 12 x 67/4 = 3 x 67 = 201 Thus, the number of bags of fruit, each containing 1/4 pounds, that can be sold is: 201/(1/4) = 201 x 4 = 804 Answer: E
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Re: A school club plans to package and sell dried fruit to raise money. Th
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24 Apr 2018, 03:05
QA E , 12*67/4 = 804/4/1/4 = 804
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Re: A school club plans to package and sell dried fruit to raise money. Th
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14 Aug 2018, 03:47
Let the maximum number of individual bags of dried fruit, each containing 1/4 pounds be "B" 1/4*B=67/4*12 (as total weight of dried fruits=67/4*12 pounds) B=804
Answer (E)



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Re: A school club plans to package and sell dried fruit to raise money. Th
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19 Aug 2018, 21:34
1 container weight = 67/4 pounds 12 containers weight = 67*12/4 = 201 pounds Number of packges that can be made of 1/4 pounds = 201/(1/4) = 201*4 = 804 Posted from my mobile device
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A school club plans to package and sell dried fruit to raise money. Th
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20 Oct 2018, 04:02
carcass wrote: A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?
A. 50
B. 64
C. 67
D. 768
E. 804 \(16\frac{3}{4}\) = \(\frac{67}{4}\) and \(\frac{67}{4}* 12 = 201\) Basically 1 pound makes 4 bags (because bag takes \(\frac{1}{4}\) pounds) Multiply 201 by 4 = 804 Answer choice E



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Re: A school club plans to package and sell dried fruit to raise money. Th
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01 Mar 2019, 11:42
Hi, we can solve this alternatively if we assume that each lot contains 17 pounds. Then total we have is 17 *12. We need to distribute them in bags which can hold upto 1/4 pounds. the total number of bags in this case would be 17*12*4= 816 Since we have taken 1/4 more than given lot size , the additional bags because of these 1/4 is = 1/4*12*4 = 12 So total number of bags are 81612= 804 Hope this helps
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Re: A school club plans to package and sell dried fruit to raise money. Th
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