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A school club plans to package and sell dried fruit to raise money. Th

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A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804

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Re: A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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New post 23 Jul 2017, 14:35
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carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing 16 \(\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?

A. 50

B. 64

C. 67

D. 768

E. 804

Total pounds of dried fruit:
12 containers * 16\(\frac{3}{4}\) lbs / container =
(12*16) + (12*\(\frac{3}{4}\)) =
(192 + 9) = 201 pounds

How many quarter-pound bags can be made from 201 total pounds?

\(\frac{201}{(\frac{1}{4})\) = 201 * 4 = 804

Answer E
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Re: A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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New post 23 Jul 2017, 14:49
carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing 16 \(\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?

A. 50

B. 64

C. 67

D. 768

E. 804


I. 12 packs containing 16.75 lbs each: Total = 12*16.75 lbs
II. Total/(1/4) = Total*4 = (12*16.75)*4 = [12*16+12*3/4]*4 = [201]*4 = 804 bags
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Re: A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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New post 23 Jul 2017, 23:37
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carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804


12 containers of dried fruit, each containing \(16\frac{3}{4}=\frac{67}{4}\) pounds = \(\frac{12*67}{4}\) pounds.

\(\frac{(\frac{12*67}{4})}{(\frac{1}{4})}=\frac{12*67}{4}*4=12*67=...4\) (something with units digit of 4 but for sure greater than 64, gives only E).

Answer; E.
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Re: A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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New post 24 Jul 2017, 09:35
option E
3/4 part of the 16 will give 3 bags.
1 pound will give 4.
Total is 16. So 16*4+3=67
Now 67 *12= 804 bags
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Re: A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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New post 24 Jul 2017, 09:41
\(12 * (\frac{3}{4} * 4 + 16 * 4) = 12 * (3+64) = 804\). Ans - E.
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Re: A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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New post 24 Jul 2017, 09:54
carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804


I would do 67/4 * 12* 4= 201*4= 804, E.
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Re: A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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New post 26 Jul 2017, 15:17
carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804


The total fruit purchased, in pounds, was:

12 x 16 ¾ = 12 x 67/4 = 3 x 67 = 201

Thus, the number of bags of fruit, each containing 1/4 pounds, that can be sold is:

201/(1/4) = 201 x 4 = 804

Answer: E
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Re: A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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New post 24 Apr 2018, 02:05
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QA E ,
12*67/4 = 804/4/1/4 = 804
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Re: A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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New post 14 Aug 2018, 02:47
Let the maximum number of individual bags of dried fruit, each containing 1/4 pounds be "B"
1/4*B=67/4*12 (as total weight of dried fruits=67/4*12 pounds)
B=804

Answer (E)
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Re: A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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New post 19 Aug 2018, 20:34
1 container weight = 67/4 pounds
12 containers weight = 67*12/4 = 201 pounds
Number of packges that can be made of 1/4 pounds = 201/(1/4) = 201*4 = 804

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A school club plans to package and sell dried fruit to raise money. Th  [#permalink]

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New post 20 Oct 2018, 03:02
carcass wrote:
A school club plans to package and sell dried fruit to raise money. The club purchased 12 containers of dried fruit, each containing \(16\frac{3}{4}\) pounds. What is the maximum number of individual bags of dried fruit, each containing \(\frac{1}{4}\) pounds, that can be sold from the dried fruit the club purchased ?


A. 50

B. 64

C. 67

D. 768

E. 804


\(16\frac{3}{4}\) = \(\frac{67}{4}\) and \(\frac{67}{4}* 12 = 201\)

Basically 1 pound makes 4 bags (because bag takes \(\frac{1}{4}\) pounds)

Multiply 201 by 4 = 804

Answer choice E
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A school club plans to package and sell dried fruit to raise money. Th &nbs [#permalink] 20 Oct 2018, 03:02
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