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Bunuel
In how many years would Bane be exactly thrice as old as his grandson?

(1) In ten years, Bane would be 30 years more than twice his grandson’s age.
(2) Ten years back, Bane was 40 years more than thrice his grandson’s age.

(1) B+10 = 30 + 2 (G+10)
B= 2G + 40

Not sufficient

(2) B-10 = 40 + 3(G-10)
B = 3G +20

Not Sufficient

On combining two equations two variables
Sufficient
D
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let the age of bane and his son be x and y years respectively
and we need to find out: In how many years would Bane be exactly thrice as old as his grandson, let n be the required no. of years after which bane would be thrice as old as his grandson
so we have,
(x+n) = 3(y+n), by solving we get: n = (x-3y)/2 or we need the value of (x-3y).
Now lets look at the given statements
(1) In ten years, Bane would be 30 years more than twice his grandson’s age.
(x+10) = 2(y+10)+30, solving it, we get: x-2y=40, we reach nowhere with this, hence insuffificent

(2) Ten years back, Bane was 40 years more than thrice his grandson’s age.
(x-10) = 3(y-10)+40, solving it, we get: x-3y=20, and hence n=20/2=10
hence sufficient

hence B
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Bunuel
In how many years would Bane be exactly thrice as old as his grandson?

(1) In ten years, Bane would be 30 years more than twice his grandson’s age.
(2) Ten years back, Bane was 40 years more than thrice his grandson’s age.

Bane -> B years
Gson-> G years
B+n = 3(G+n)
n = ?

1) B+10 = 2(G+10)+30
=> B = 2G+40
And B = 3G+2n
=> G = 40-2n
n=?
Insufficient.

2) B-10 = 3(G-10)+40
=> B = 3G + 20
and B = 3G + 2n
=> n = 10
Sufficient.

The answer should be B.
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