pandoraUM
What is the fastest way to solve this?
\(\frac{(0.513)(0.488)(0.942)}{(0.684)(0.314)(0.183)}\)
a) 4
b) 5
c) 6
d) 7
e) 8
Useful concept: \(\frac{A \times B \times C}{D \times E \times F} = \frac{A}{D} \times \frac{B}{E} \times \frac{C}{F}\)Strategy: As you can imagine, we certainly don't want to actually find the product in the numerator and the product in the denominator and then divide the results. Instead, let's invest a little bit of time identifying any pairs of values that might simplify today " nice" fraction.First off, I recognize that \(0.942\) is exactly \(3 \times 0.314\).
So, let's rewrite our expression as follows: \(\frac{(0.513)(0.488)(0.942)}{(0.684)(0.314)(0.183)} = \frac{0.942}{0.314} \times \frac{(0.513)(0.488)}{(0.684)(0.183)}= 3 \times \frac{(0.513)(0.488)}{(0.684)(0.183)}\)
Next, I know that \(3 \times 0.18 = 0.54\), which means \(\frac{0.54}{0.18} = 3\)
The fraction \(\frac{0.513}{0.183}\) kind of resembles \(\frac{0.54}{0.18} = 3\).
However, since \(0.513\) is a bit smaller than \(0.54\), and since \(0.183\) is a teeny bit bigger than \(0.18\), we know that \(\frac{0.513}{0.183}\) will be a little bit smaller than \(3\).
So, we can rewrite our expression as follows: \(3 \times \frac{(0.513)(0.488)}{(0.684)(0.183)} = 3 \times \frac{0.513}{0.183} \times \frac{0.488}{0.684} = 3 \times little less than3 \times \frac{0.488}{0.684} \)
Finally, we know that \(\frac{4}{6} = \frac{2}{3}\), and \(\frac{440}{660} = \frac{2}{3}\), and \(\frac{460}{690} = \frac{2}{3}\)
Since \(0.488\) is a bit bigger than \(460\), we can conclude that \(\frac{0.488}{0.684}\) is a little bit bigger than \(\frac{2}{3}\).
So, our expression becomes:
\(3 \times little less than3 \times \frac{0.488}{0.684} = 3 \times (little less than3) \times (a little more than \frac{2}{3})\)
The "little more than part" some What cancels out with the " little less than" part to get: \(3 \times 3 \times \frac{2}{3}\), which evaluates to be \(6\)
Answer: C