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(0.513)(0.488)(0.942)/(0.684)(0.314)(0.183)
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pandoraUM
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Joined: 08 Apr 2018
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(0.513)(0.488)(0.942)/(0.684)(0.314)(0.183) [#permalink] New post  17 Apr 2018, 19:46
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A
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C
D
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Difficulty:

65% (hard)

Question Stats:

56% (01:59) correct 44% (01:50) wrong based on 444 sessions

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What is the fastest way to solve this?

\(\frac{(0.513)(0.488)(0.942)}{(0.684)(0.314)(0.183)}\)


a) 4
b) 5
c) 6
d) 7
e) 8
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u1983
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(0.513)(0.488)(0.942)/(0.684)(0.314)(0.183) [#permalink] New post  17 Apr 2018, 20:11
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pandoraUM wrote:
What is the fastest way to solve this?

\(\frac{(0.513)(0.488)(0.942)}{(0.684)(0.314)(0.183)}\)


a) 4
b) 5
c) 6
d) 7
e) 8


I would like to use approximation of numbers as below:

\(\frac{(0.513)(0.488)(0.942)}{(0.684)(0.314)(0.183)}\)
=\(\frac{(513)(488)(942)}{(684)(314)(183)}\)
apx=\(\frac{(500)(500)(950)}{(700)(300)(190)}\)
apx=\(\frac{(5)(5)(5)}{(7)(3)}\)
apx=\(\frac{(5)(5)(5)}{(7)(3)}\)
apx=\(\frac{(125)}{(21)}\)
apx=6....................(21*6=126)................................Thus Answer c
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Tulkin987
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Re: (0.513)(0.488)(0.942)/(0.684)(0.314)(0.183) [#permalink] New post  17 Apr 2018, 22:25
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pandoraUM wrote:
What is the fastest way to solve this?

\(\frac{(0.513)(0.488)(0.942)}{(0.684)(0.314)(0.183)}\)


a) 4
b) 5
c) 6
d) 7
e) 8


\(\frac{(0.513)(0.488)(0.942)}{(0.684)(0.314)(0.183)}\) \(=\) \(\frac{(3*0,171)(8*0,061)(3*0,314)}{(4*0,171)(0.314)(3*0,061)}\) \(=\) 6

Answer: C
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push12345
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Re: (0.513)(0.488)(0.942)/(0.684)(0.314)(0.183) [#permalink] New post  02 May 2018, 05:57
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Take approximate values and solve

0.5*0.5*1/(0.7*0.3*0.2)
=125/21
Approx 6
as 21*6=216

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dabaobao
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Re: (0.513)(0.488)(0.942)/(0.684)(0.314)(0.183) [#permalink] New post  15 Jul 2020, 03:06
pandoraUM wrote:
What is the fastest way to solve this?

\(\frac{(0.513)(0.488)(0.942)}{(0.684)(0.314)(0.183)}\)


a) 4
b) 5
c) 6
d) 7
e) 8


1) Remove all the decimals
2) 942/314 = 3
3) If you can't see other obvious big factors, then just try to use smaller factors to reduce.
4) You'll get reduced fraction as 6.

ANSWER: C
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Re: (0.513)(0.488)(0.942)/(0.684)(0.314)(0.183) [#permalink]
15 Jul 2020, 03:06
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