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Let a = Hundreds Digit Number, b = Tens Digit Number, c = Units Digit Number
a+b+c = 18 .... (i)
b = 2a & a = c/3 => 3a = c
(i)=> a + 2a + 3a = 18 => 6a = 18 => a = 3
so b = 6, c = 9
Number = 369 ...... ANSWER = B
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There are only two option with sum of their digits equal to 18.

B) 369
D) 855

Option D clearly do not satisfies any given conditions in question.

Then , answer is option B.
And option B also satisfies every condition given in question.

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