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Jazzmin
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At a football game between team A and team B, 95000 fans are in attend 15 Dec 2018, 21:50
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95% (hard)

Question Stats:

48% (02:35) correct 52% (02:45) wrong based on 191 sessions

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At a football game between team A and team B, 95000 fans are in attendance. Eighty percent of those fans are rooting for team A. An unknown number of team B fans leave the stadium, while all of the team A fans remain. Team A fans now comprise 95 percent of the total number of fans at the game. Assuming that none of the fans are fans of both team A and team B, how many team B fans are left in the stadium?

1. 4000

2. 4750

3. 10000

4. 15000

5. 19000
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A
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vishalkazone
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At a football game between team A and team B, 95000 fans are in attend 15 Dec 2018, 23:15
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Suppose total Attendance = 100
Team A supporter : 80
Team B Supporter: 20
Now some of team B supporter Leave Suppose: x
Total attendance after Some of B supporter leave: 100-x
Now given (100-x) * 0.95 = 80
95-0.95x =80
0.95x = 15
X= 15.8 ( for every 100 attendance)
For 95000
(15.8 * 95000) / 100
= approx. 15000

Answer D (4)

i think Given OA is wrong..
Please confirm Jazzmin
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Jazzmin
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At a football game between team A and team B, 95000 fans are in attend 16 Dec 2018, 00:12
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Jazzmin
At a football game between team A and team B, 95000 fans are in attendance. Eighty percent of those fans are rooting for team A. An unknown number of team B fans leave the stadium, while all of the team A fans remain. Team A fans now comprise 95 percent of the total number of fans at the game. Assuming that none of the fans are fans of both team A and team B, how many team B fans are left in the stadium?

1. 4000

2. 4750

3. 10000

4. 15000

5. 19000
Show more


This is my approach
80 percent of the fans are rooting for team A which means 20 percent are rooting for team B since no players are rooting for both
80 percent of 95000 is 76000 root for team A and the rest 19000 root for team B
Now, x number of fans rooting for B leave the stadium.
So, 76000 comprise of 95 % of the stadium which means the rest 5% are left in the stadium which root for team B.
76000 is 95% of 80000.
Which means the rest 4000 are rooting for team B.
The question here is how many team B fans are left inside the stadium which is 4000
Your answer is correct if the question was ¨how many team B fans left the stadium¨
I hope this helps. Pls correct me if I am wrong.
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ksrutisagar
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At a football game between team A and team B, 95000 fans are in attend 17 Dec 2018, 04:14
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Since the number of fans of Team A is unchanged

We can Equate (80/100) * 95000 = (95/100) * x
Where x is the total number of fans left after some fans of Team B leave

By inspection x = 80000

Number of fans of Team B left in the stadium = 5% of 80000 = 4000
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At a football game between team A and team B, 95000 fans are in attend 25 Apr 2019, 06:19
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let say,
The total of people, X = 95000


Before,
The number of A supporter, A = 0.8x ,
The number of B supporter, B = 0.2x

After,
The number of A supporter, A = 0.8x ,
The number of B supporter who leaves the game, m
The number of B supporter who remains in the game, C = 0.2x -m

Therefore,

A/(A + C) = 0.95
0.8X / (0.8x + C ) = 0.95
C = 4000
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At a football game between team A and team B, 95000 fans are in attend 04 Aug 2020, 04:51
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vishalkazone
Suppose total Attendance = 100
Team A supporter : 80
Team B Supporter: 20
Now some of team B supporter Leave Suppose: x
Total attendance after Some of B supporter leave: 100-x
Now given (100-x) * 0.95 = 80
95-0.95x =80
0.95x = 15
X= 15.8 ( for every 100 attendance)
For 95000
(15.8 * 95000) / 100
= approx. 15000

Answer D (4)

i think Given OA is wrong..
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Question is how many people are left, not how many people left.
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At a football game between team A and team B, 95000 fans are in attend 29 Jul 2022, 11:42
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95,000

A - 80% = 4/5th of 95,000
B - 20% = 1/5th of 95,000

B = 19,000, so A = 76,000

So, 76,000 = 95% of total


then (Total) * (95/100) = 76,000

Total = (19*4000) * (100/(19*5))= 80,000

B = Total - A = 80,000 - 76,000 = 4,000
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At a football game between team A and team B, 95000 fans are in attend 29 Jul 2022, 16:26
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Jazzmin
At a football game between team A and team B, 95000 fans are in attendance. Eighty percent of those fans are rooting for team A. An unknown number of team B fans leave the stadium, while all of the team A fans remain. Team A fans now comprise 95 percent of the total number of fans at the game. Assuming that none of the fans are fans of both team A and team B, how many team B fans are left in the stadium?

1. 4000

2. 4750

3. 10000

4. 15000

5. 19000
Show more

Two ways.

First, Math.
95000/5 = 19000. We start with 19000 B. So, 76000 A. We end with 76000 and __ B. Look at the answer choices. Which do we need to add to 76000 to make the 76000 95% of the total?
Answer choice A.

Second, Ballparking.
Let's just call it 100000. We start with 80000 A and 20000 B. We end with 80000 A and 80000/19 B. 80000/20 = 4000, so we want a little more than that. But then we also want a little less because we really started with 95000, not 100000. Should balance out to be right around 4000. C, D, and E are clearly wrong. B looks closer than it is; it's really off by almost 20%.
Answer choice A.


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At a football game between team A and team B, 95000 fans are in attend 12 Jun 2024, 06:18
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