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73*75= (5*7) mod 34= 1 (mod 34)
78=10 mod 34
57*197= (-11*-7) mod 34=9 mod 34

73 *75 *78 *57 *197= 90 mod 34= 22 mod 34

Remainder we will get is 22


LUCIFER1703
Find the remainder when 73 *75 *78 *57 *197 is divided by 34.

(a) 22
(b) 30
(c) 15
(d) 28
(e) 45

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(73/34)Rof = 5

*

(75/34)Rof = 7

*

(78/34)Rof = 10

*

(57/34)Rof = 23

*

(197/34)Rof = 27
_______________

(5*7*10*23*27) / (34) Rof = ?

(35/34)Rof = 1
*
(230/34)Rof = -8
*
(27/34)Rof = -7

1 * -8 * -7 = 56 ------> Removing the Excess Remainder of 56

56 - 34 = Remainder of 22

-A-
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LUCIFER1703
Find the remainder when 73 *75 *78 *57 *197 is divided by 34.

(a) 22
(b) 30
(c) 15
(d) 28
(e) 45

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N = 73 *75 *78 *57 *197 = (68 + 5)*(68 + 7)*(68 + 10)*(68 - 11)*(204 - 7)

All terms will be a multiple of 34 except the last term obtained by multiplying 5*7*10*(-11)*(-7)

5*7*10*(-11)*(-7) = 35 * 110*7 = (34 + 1)*(102 + 8)*7

All terms will be a multiple of 34 except the last term obtained by multiplying 1*8*7 = 56

When 56 is divided by 34, remainder is 22.

Answer (A)
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