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Bunuel
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I think D

Max = 80%
Min = (100-95 + 100-80 + 100-84 + 100-90) = 51%
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IMO, the answer should be (C), based upon the concept of minimizing and values for each catergory:

I(exactly 1) + II (exactly 2) + III (exactly 3) + IV (exactly 4) = 100 - (eqn 1)

1*I + 2*II + 3*III + 4*IV = 349 - (eqn. 2)

Solve these two eqns,

II + 2*III + 3*IV = 249 - (eqn. 3)
Now if you put IV=49, then you have to put III= 51 , and subsequently I=0 & II=0

this satisfies the eqn. 1 & eqn. 3

hence, (C)
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maximum= minimum of all which is 80
minimum= (95'+80'+84'+90')'=(5+20+16+10)'=(51)'=49
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