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Let number of $1.25 greeting cards be x, then number of 85-cent greeting cards will also be x.
Total number of cards = \(2x\)

Total cost = $25.20
\(1.25x + 0.85x = 25.2\)
\(2.1x = 25.2\)
\(x = \frac{252}{21}\)

\(x = 12\)

Total number of cards = \(2 \times 12 = 24\)

OA,D
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1,25x + 0,85x = 25,2
1,25(12) + 0,85(12) = 25,2
15 + 10,2 = 25,2
12x2=24

IMHO --> D
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TIME 0:57

IMO B
OA D

Kindly see the attachment. I have documented the steps that I took during the exam mode for this question.


UPDATE: I even wrote that 2n needs to be calculated. And I still marked n. BIG MISTAKE.

Attachments

1.jpeg
1.jpeg [ 90.2 KiB | Viewed 4399 times ]

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IMO-D
women buy X cards after paying =1.25x
And another X cards after paying =.85x

1.25x+.85x=25.2
2.1x=25.2
X=12

Total no of cards =2x
=2*12
=24

Posted from my mobile device
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Quote:
A woman buys equal numbers of $1.25 and 85-cent greeting cards for $25.20. How many cards does she buy?

A. 8
B. 12
C. 20
D. 24
E. 28

T = x + y, where T is the number of total cards, x is the number of 1.25 cards and y is the number of .85 cards. We are told that 25.20 = 1.25x + .85y. Since x = y, we can use substitution to solve for x => x = 12. Since T = x + y and x=y, T = 12 + 12 = 24.

ANSWER: D
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x(1.25+0.85)=25.2
x(2.1)=25.2
x=12
so the woman buys 12 cars of $1.25 and 12 cards of 85-cent
therefore, she buys total of 24 cards
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Quote:
woman buys equal numbers of $1.25 and 85-cent greeting cards for $25.20. How many cards does she buy?

A. 8
B. 12
C. 20
D. 24
E. 28

1.25x+0.85x=25.2, 2.1x=25.2, x=12
2x=24

Ans (D)
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A woman buys equal numbers of $1.25 and 85-cent greeting cards for $25.20. How many cards does she buy?

A. 8
B. 12
C. 20
D. 24
E. 28

1 dollar = 100 cents
so,
125x + 85y = 2520
since x=y,
210x = 2520
x=12
so total =24

Ans D
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