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Asked: How many possible values of m satisfy the inequality |m + 1| – |m – 3| > 4, if m is an integer?

|m + 1| – |m – 3| > 4
|m+1| > 4+ |m-3|

Case 1: m<-1
-m-1 - (-m+3) > 4
-4 > 4
NOT FEASIBLE

Case 2: -1<=m<3
m+1 - (-m+3) >4
2m -2 > 4
m > 3
NOT FEASIBLE

Case 3: m>=3
m+1 - (m-3) > 4
4>4
NOT FEASIBLE

IMO A
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|m + 1| – |m – 3| > 4
We have three cases:

1st case: m>=3. Then m+1-m+3=4. In this case we do not have any solution.

2nd case: -1=<m<3. Then m+1-3+m=2m-2>4 ----> m-1>2 ----> m>3. In this case also we don't have any solution.

3rd case: m<-1. Then -m-1-3+m=-4. In this case also we don't have any solution.

So the inequality does not have any solution. A)
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Three areas are on the number line:

1) m < -1

Here, the inequality is:

-(m+1) + (m-3) > 4

-4 > 4

Not possible.

2) m between 1 and 3

Here, the inequality is:

(m+1) + (m-3) > 4

2m - 2 > 4

2m > 6

m > 3

Not possible, since m is between 1 and 3

3) m > 3

Here, the inequality is:

(m+1) - (m-3) > 4

4 > 4

Not possible.

So, no solution.
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How many possible values of m satisfy the inequality |m + 1| – |m – 3| > 4, if m is an integer?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4


For those, who want to understand the concept of MOD.
The question asks us whether the distance of m from -1 is greater than the distance of m from 3 by a quantity of 4.

Let us draw a number line, and mark -1 with brown and 3 with blue.
m can be at three locations
1) On the left side of -1, shown as m1...
Clearly BROWN line is closer to m than BLUE line, so answer will always be negative and -4....... Is -4>4?...NO, so no value will fit in.
2) In between 3 and -1, shown as m2...
Now, it is the SUM that is 4, so the difference has to be less than 4. It will be max at 3, that is 4, and minimum at -1, that is -4....... Is (-4 to 4) >4?...NO, so no value will fit in.
3) On the right side of 3, shown as m...
Clearly BLUE line is closer to m than BROWN line, so answer will always be positive, but there is OVERLAP after 3, so Brown-Blue=4 ....... Is 4>4?...NO, so no value will fit in.

Hence 0 values will fit in.'

A
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Can we solve this by squaring as well?

(M+1+M-3) (M+1-M+3) >16
(2M-2)(4)>16 (dividing the equation by 2)
(M-1)>4
M>5

checking by replugging any value which is M>5.
the answer will always be 4>4 which can't be possible. Hence, 0.

Posted from my mobile device
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great solution! thanks, it's so elegant.
QuantMadeEasy
Quote:
How many possible values of m satisfy the inequality |m + 1| – |m – 3| > 4, if m is an integer?
Step 1: Understanding the question
|m + 1| is the distance of m from -1
|m – 3| is the distance of m from 3
m lies in the region a, b or c (refer to the attachment)
Difference between (distance of m from -1) and (distance of m from 3) is required

Step 2: Calculation
As the distance between -1 and 3 is 4
Hence |m + 1| – |m – 3| can be maximum 4, but cannot be greater than 4

A is correct
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