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ANSWER B
Area of unshaded region = Area of square - Area of shaded region
(2r*2r) - (4*(pi*r*r)/4) = \(4r^2 - \pi r^2\)



Bunuel

The shaded area in the figure shown consists of quarter circles. If each quarter circle has radius r, what is the area of the unshaded region in terms of r?


A. \(3r^2 - \pi r^2\)

B. \(4r^2 - \pi r^2\)

C. \(5r^2 - \pi r^2\)

D. \(6r^2 - \pi r^2\)

E. \(7r^2 - \pi r^2\)


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Bunuel

The shaded area in the figure shown consists of quarter circles. If each quarter circle has radius r, what is the area of the unshaded region in terms of r?


A. \(3r^2 - \pi r^2\)

B. \(4r^2 - \pi r^2\)

C. \(5r^2 - \pi r^2\)

D. \(6r^2 - \pi r^2\)

E. \(7r^2 - \pi r^2\)


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2020-10-27_14-09-22.png
Area of the square is \(2r^2 = 4r^2\)

Area of 4 quarter circles = 1 full circle is \(πr^2\)

So, Area of unshaded region is B. \(4r^2 - \pi r^2\)
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The shaded area in the figure shown consists of quarter circles. If each quarter circle has radius r, what is the area of the unshaded region in terms of r?

Given:
The radius of each quater circle = r

We know that since side of square is equal to radius of 2 quarter circle = 2r

Area of square = \(4r^2\)

Circle:
Area of circle = \(\pi r^2\)
Now we have four quarter circle each with radius r , so area of one quarter circle =\(\pi r^2/4\)

We have 4 similar quarter circle, so the sum of area of 4 quarter circle = 4 * \(\pi r^2/4\) = \(\pi r^2\)

Area of unshaded region = Area of square - Area of shaded region

\(4r^2\) - \(\pi r^2\)

Ans: B
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