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22 Apr 2021, 01:30
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D
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Difficulty:
5%
(low)
Question Stats:
86% (01:05) correct
14%
(01:35)
wrong
based on 58
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The surface area of a sphere is \(4πR^2\), and the volume of a sphere is \((\frac{4}{3})·π·R^3\), where R is the radius of the sphere. If the volume of a certain sphere is double the surface area of that sphere, what is the radius of that certain sphere?
A. 1.5
B. 6/π
C. 1.5π
D. 6
E. 6π
A. 1.5
B. 6/π
C. 1.5π
D. 6
E. 6π
22 Apr 2021, 03:03
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Ans D
Since volume = 2* surface area
4/3 * pie * R^3 =2*4 *pie*R^2
R=6
Ans D
Since volume = 2* surface area
4/3 * pie * R^3 =2*4 *pie*R^2
R=6
Ans D
22 Apr 2021, 03:15
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Since, volume = 2* surface area
4/3 * pie * R^3 =2*4 *pie*R^2
R=6
D is the right answer
4/3 * pie * R^3 =2*4 *pie*R^2
R=6
D is the right answer
