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Bunuel
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Given,
DA = DB, CD = CB and AB = AC
We need to find value of x.
DA = DB
which implies angle DBA = x (isosceles triangle)
Now in triangle BDA,
x+x+ ADB = 180
ADB = 180 - 2x
angle BDC = 2x (supplementary angle)

Now in triangle BDC,
2x + 2x + BCD = 180
BCD = 180 -4x

Also given
AB = AC
angle ABC = angle ACB
3x = 180 -4x
7x = 180
x = 180/7

IMO A
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I have listed the steps in the picture attached. Choice A
Attachments

File comment: Drawing attempt
IMG-2042.jpg
IMG-2042.jpg [ 3.5 MiB | Viewed 3037 times ]

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As, 180-p = 180- 2x or, p = 2x

So, x+ (x+2x) + (x+2x) = 180 or, x = 180/7.

I think A. :)
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this Q. is an application of the following two theorems:
1: Angles opposite to equal sides in a triangle are equal.
2: Exterior angle is equal to the sum of interior opposite angles


I hope the rest is easy to solve !!!! check the solution image uploaded by zanto.
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IMO A,

Post making all the angles in ABC interms of x , We know sum of angles is 180

Hence x is 180/7.

Posted from my mobile device
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IMG_20210710_184821.jpg
IMG_20210710_184821.jpg [ 62.37 KiB | Viewed 2824 times ]

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