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Updated on: 03 Jun 2024, 03:49
Originally posted by NoHalfMeasures on 14 Oct 2021, 10:33.
Last edited by Bunuel on 03 Jun 2024, 03:49, edited 3 times in total.
Last edited by Bunuel on 03 Jun 2024, 03:49, edited 3 times in total.
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
35% (01:48) correct
65%
(01:35)
wrong
based on 113
sessions
History
Date
Time
Result
Not Attempted Yet
If \(x + \sqrt{x} - 20 = 0\), what is the sum of roots of the equation?
A. 41
B. 1
C. 3
D. 16
E. 0
A. 41
B. 1
C. 3
D. 16
E. 0
14 Oct 2021, 16:33
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let y = sqrt(x)
Then the eq becomes y^2 + y -20 = 0
y^2 + 5y -4y -20 = 0
y(y+5) -4(y+5)=0
y = -5 or y = 4
Therefore -
sqrt(x) = -5 INCORRECT
OR
sqrt(x) = 4
We are require to find the value of x, Therefore x = 4^2 = 16
I don't know how to do the math equations on here so sorry
Then the eq becomes y^2 + y -20 = 0
y^2 + 5y -4y -20 = 0
y(y+5) -4(y+5)=0
y = -5 or y = 4
Therefore -
sqrt(x) = -5 INCORRECT
OR
sqrt(x) = 4
We are require to find the value of x, Therefore x = 4^2 = 16
I don't know how to do the math equations on here so sorry
samarpan.g28
09 Jun 2024, 13:40
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SShareef
I agree with your solution. I believe 16 is the only root of this equation, so the sum of roots becomes 16. KarishmaB can you please correct me if I am wrong?
