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(100 - x) = y - (2y/5)
100 - x = 3y/5

Y = 75
X = 55
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Let us take the capacity of each beaker as 100 ml

water in beaker in X and Y = x ml and y ml respectively ( x% amd y%)

After transfer X is full = 100, Y is 2/5 full = 40ml

Hence total = 100+40= 140ml

or x+y = 140

Only (65, 75) satisfies the above relation. 


(PS : Follow this checking approach:  x cannot be 55 , coz corresponding y should be 85 )
Sajjad1994
A chemist starts with two equally sized beakers, labeled X and Y, that each contains a different amount of water. X is x% full and Y is y% full. The chemist then pours water from beaker Y until beaker X is completely full and Y is now 2/5 full. If beaker Y initially contained more water than did beaker X, which of the following could be the values of x and y?
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I think
X 65
Y 75

Let N be the percentage of water transferred from Y to X. We have:
X+N=100
Y-N=40
X<Y

So: X+Y=140
X<Y

The only combination that satisfies is
X=65
Y=75
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Let's break this down step by step.

Understanding the Setup:
- Two beakers of equal size. Beaker X starts x% full, Beaker Y starts y% full.
- Water is poured from Y into X until X is completely full (100%).
- After pouring, Y is 2/5 = 40% full.
- Key constraint: y > x (Y initially had MORE water than X).

Step 1: How much water was poured?
X went from x% to 100%, so the amount poured INTO X is (100 - x)%.

Step 2: Set up the equation for Y.
Y started at y% and lost (100 - x)%, ending at 40%.

y - (100 - x) = 40
y - 100 + x = 40
x + y = 140

So the two unknowns must add up to 140.

Step 3: Check which pair from the choices sums to [b]140.[/b]
- 55 + 8585 is not a choice
- 60 + 8080 is not a choice
- 65 + 75 → Both are choices! Sum = 140. Check: 75 > 65, so y > x is satisfied.
- 70 + 70 → Sum = 140, but this means y = x, which violates y > x.
- 50 + 9050 is not a choice

The only valid pair is x = 65 and y = 75.

Quick verification: X starts at 65%, needs 35% more to be full. Y starts at 75%, gives away 35%, and is left with 75 - 35 = 40% = 2/5. Y initially had more water (75% > 65%). Everything checks out.

Answer: x = 65 (Row 3, Column A) and y = 75 (Row 5, Column B)
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Simplest approach:
Take 100ml.
2/5*100 = 40
What is the final result after the pouring?
X = 100, Y=40
Total = 140
Find x+y=140.
Answer: 65,75
Sajjad1994
A chemist starts with two equally sized beakers, labeled X and Y, that each contains a different amount of water. X is x% full and Y is y% full. The chemist then pours water from beaker Y until beaker X is completely full and Y is now 2/5 full. If beaker Y initially contained more water than did beaker X, which of the following could be the values of x and y?
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