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E
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Difficulty:
55%
(hard)
Question Stats:
57% (01:39) correct
43%
(01:29)
wrong
based on 220
sessions
History
Date
Time
Result
Not Attempted Yet
What is the number of distinct positive factors of the product of 484 and 124?
(A) 3
(B) 4
(C) 7
(D) 8
(E) 30
(A) 3
(B) 4
(C) 7
(D) 8
(E) 30
06 Apr 2022, 10:14
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First we want to find the prime factors of each number:
484 = 2^2 * 11^2
124 = 2^2 * 31
Therefore their product:
484*124 = 2^4 * 11^2 * 31
Now to find the distinct number of factors we take the the powers of each distinct prime number add one to it and multiply them together:
(4+1) * (2+1) * (1+1) = 30
==> E
484 = 2^2 * 11^2
124 = 2^2 * 31
Therefore their product:
484*124 = 2^4 * 11^2 * 31
Now to find the distinct number of factors we take the the powers of each distinct prime number add one to it and multiply them together:
(4+1) * (2+1) * (1+1) = 30
==> E
