Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 1612:00 PM EDT
-11:59 PM EDT
You’re first to know: Save $200 on GMAT prep starting tomorrow, 4/13. Get 6 official practice tests and study with real questions. Be ready to save!
Apr 2212:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2301:30 AM EDT
-02:30 AM EDT
Struggling with GMAT Verbal as a non-native speaker? Harsh improved his score from 595 to 695 in just 45 days—and scored a 99 %ile in Verbal (V88)! Learn how smart strategy, clarity, and guided prep helped him gain 100 points.
Apr 2308:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
25 Jun 2022, 01:46
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
39% (02:30) correct
61%
(02:45)
wrong
based on 98
sessions
History
Date
Time
Result
Not Attempted Yet
If a and b are integers, and |a| > |b|, is a · |b| < a – b?
(1) a < 0
(2) ab > 0
(1) a < 0
(2) ab > 0
wadhwakaran
Joined: 31 Mar 2022
Last visit: 22 Jul 2025
Posts: 260
Given Kudos: 19
Location: India
Concentration: General Management, International Business
Schools: INSEAD Aug'24 intake Oxford Said'25 Judge '25 Imperial'25 HEC Sep'24 Intake LBS '26 ISB '27
GMAT 1: 700 Q50 V35
GPA: 2.8
Products:
Schools: INSEAD Aug'24 intake Oxford Said'25 Judge '25 Imperial'25 HEC Sep'24 Intake LBS '26 ISB '27
GMAT 1: 700 Q50 V35
Posts: 260
25 Jun 2022, 03:52
Kudos
Bookmarks
S(1) a < 0
a is a negative integer
|a|>|b|
Assume a=-3, |b|=1
meaning thereby that b can take two values -1 and +1
Case 1 (a=-3, b=-1)
a*|b|= -3*1=-3
a – b= -3-(-1)=-3+1=-2
a*|b|<a-b (yes)
Case 2 (a=-3, b=1)
a*|b|= -3*1=-3
a – b= -3-(1)=-3-1=-4
a*|b|<a-b (No)
Therefore, S(1) is not sufficient.
S(2) ab > 0
Case I a=3, b=1
a*|b|= 3*1=3
a – b= 3-(1)=3-1=2
a*|b|<a-b (No)
Case I a=-3, b=-1
a*|b|= -3*1=-3
a – b= -3-(-1)=-3+1=-2
a*|b|<a-b (Yes)
Therefore, S(2) is not sufficient.
Combining S(1) and S(2)
a<0 and ab>0
This results in only one case i.e. when both a and b are <0
Case I a=-3, b=-1
a*|b|= -3*1=-3
a – b= -3-(-1)=-3+1=-2
a*|b|<a-b (Yes)
Case II a=-1 , b=-1/2
a*|b|= -1*1/2=-0.5
a – b= -1-(-1/2)=-1+0.5=-0.5
a*|b|<a-b (No)
Therefore, S(1) and S(2) together are not sufficient.
a is a negative integer
|a|>|b|
Assume a=-3, |b|=1
meaning thereby that b can take two values -1 and +1
Case 1 (a=-3, b=-1)
a*|b|= -3*1=-3
a – b= -3-(-1)=-3+1=-2
a*|b|<a-b (yes)
Case 2 (a=-3, b=1)
a*|b|= -3*1=-3
a – b= -3-(1)=-3-1=-4
a*|b|<a-b (No)
Therefore, S(1) is not sufficient.
S(2) ab > 0
Case I a=3, b=1
a*|b|= 3*1=3
a – b= 3-(1)=3-1=2
a*|b|<a-b (No)
Case I a=-3, b=-1
a*|b|= -3*1=-3
a – b= -3-(-1)=-3+1=-2
a*|b|<a-b (Yes)
Therefore, S(2) is not sufficient.
Combining S(1) and S(2)
a<0 and ab>0
This results in only one case i.e. when both a and b are <0
Case I a=-3, b=-1
a*|b|= -3*1=-3
a – b= -3-(-1)=-3+1=-2
a*|b|<a-b (Yes)
Case II a=-1 , b=-1/2
a*|b|= -1*1/2=-0.5
a – b= -1-(-1/2)=-1+0.5=-0.5
a*|b|<a-b (No)
Therefore, S(1) and S(2) together are not sufficient.
25 Jun 2022, 05:34
Kudos
Bookmarks
I think C is the answer, as it is given that a and b are integers.
