Three vessels A, B and C of capacity 120 litres each contain a mixture of alcohol and spirit. Vessel A contains 100 litres of the mixture with 65% alcohol. Vessel B has 70% alcohol and this vessel is half empty. The vessel C has 80 litres of mixture out of which 20 litres are spirit. Now, the mixture from vessel A is poured into vessel B until vessel B is completely filled. Then the mixture from vessel B is poured into vessel until C is completely filled. Now the entire mixture from vessel C is poured into the vessels A and B.
What is the ratio of alcohol in vessels A and B ?
Vessel A:
Total = 100 litres
Alcohol = 65%*100 =65 litres
Vessel B:
Total = 50%*120 = 60 litres
Alcohol = 70%*60 = 42litres
Vessel C:
Total = 80 litres
Alcohol = 80-20 = 60 litres
% alcohol = 60/80 =0.75 = 75%
Now, the mixture from vessel A is poured into vessel B until vessel B is completely filled.
Vessel A:
Total = 100-60 =40 litres
Alcohol = 65% of 40 L= 26 litres
Vessel B:
Total = 60+60= 120 litres
Alcohol = 42 + (65-26) = 81 litres
Alcohol % = 81/120=0.675 = 67.5%
Then the mixture from vessel B is poured into vessel until C is completely filled.
40 litres of vessel B is poured in vessel C
Vessel B:
Total = 120-40= 80 litres
Alcohol = 81/120*80=54 litres
Vessel C:
Total = 80+40=120 litres
Alcohol = 60 + (81-54) = 87 litres
% alcohol = 87/120=0.725 = 72.5%
Now the entire mixture from vessel C is poured into the vessels A and B.
Vessel A:
Total = 40+ 80= 120litres
Alcohol = 26+ 87/120*80 =84 litres
Vessel B:
Total = 80+40=120 litres
Alcohol = 54+87/120*40=83 litres
the ratio of alcohol in vessels A and B = 84/83
IMO C