Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 3001:30 AM EDT
-02:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2912:30 AM EDT
-01:30 AM EDT
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
May 0111:00 AM PDT
-12:00 PM PDT
Free- full-length test + 15 concept videos + 150+ short videos + study plan!
May 0306:30 AM PDT
-08:30 AM PDT
Verbal trouble on GMAT? Fix it NOW! Join Sunita Singhvi for a focused webinar on actionable strategies to boost your Verbal score and take your performance to the next level.
14 Mar 2023, 12:30
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
68% (02:32) correct
32%
(02:13)
wrong
based on 394
sessions
History
Date
Time
Result
Not Attempted Yet
How many different three-digit numbers can be formed which contain two digits that are the same, and a third digit that is different from the other two?
A. 196
B. 216
C. 243
D. 256
E. 316
A. 196
B. 216
C. 243
D. 256
E. 316
20 Mar 2023, 02:27
Kudos
Bookmarks
How many different three-digit numbers can be formed which contain two digits that are the same, and a third digit that is different from the other two?
We have 9 choice of digits for Hundred place (as 0 can't be used), 10 choice of digits for Tens place and 10 choice of digits for Ones place.
Case I - first two digits are same and third digit is different:
9*1*9 = 81
Case II - first and third digits are same and second digit is different:
9*9*1 = 81
Case III - Last two digits are same and first digit is different:
9*9*1 = 81
So there are total of 81 + 81 + 81 = 243 such numbers.
Answer C
We have 9 choice of digits for Hundred place (as 0 can't be used), 10 choice of digits for Tens place and 10 choice of digits for Ones place.
Case I - first two digits are same and third digit is different:
9*1*9 = 81
Case II - first and third digits are same and second digit is different:
9*9*1 = 81
Case III - Last two digits are same and first digit is different:
9*9*1 = 81
So there are total of 81 + 81 + 81 = 243 such numbers.
Answer C
15 Aug 2024, 11:42
Kudos
Bookmarks
$!vakumar.m
In Case 3, wouldnt it be 9*10*1 as 0 can be used for tens and ones place. Could you please explain? @$!vakumar.m Bunuel
