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RenB
Joined: 13 Jul 2022
Last visit: 30 Apr 2026
Posts: 388
Given Kudos: 302
Location: India
Concentration: Finance, Nonprofit
Schools: Stanford '26 Wharton '26 (D) Booth '26 (D) Yale '26 (D) CBS '26 (A$$$) Darden '26 (WL) HBS '26 (D) Ross '26 (A$$$$) LBS '26 (D) Tuck '26 (A$$) Kellogg '26 (A)
GMAT Focus 1: 715 Q90 V84 DI82 
GPA: 3.74
WE:Corporate Finance (Consulting)
Schools: Stanford '26 Wharton '26 (D) Booth '26 (D) Yale '26 (D) CBS '26 (A$$$) Darden '26 (WL) HBS '26 (D) Ross '26 (A$$$$) LBS '26 (D) Tuck '26 (A$$) Kellogg '26 (A)
GMAT Focus 1: 715 Q90 V84 DI82
Posts: 388
20 Sep 2023, 18:49
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
63% (03:19) correct
37%
(03:19)
wrong
based on 445
sessions
History
Date
Time
Result
Not Attempted Yet
In a certain meatpacking plant, one-fifth of the shipments are tainted with salmonella, and 80 percent of the shipments with salmonella are rejected. If the total number of rejected shipments is equal to one-third of the number of untainted shipments that are NOT rejected, approximately what percent of the rejected shipments are NOT tainted with salmonella?
(A) 8%
(B) 16%
(C) 20%
(D) 24%
(E) 33.3%
(A) 8%
(B) 16%
(C) 20%
(D) 24%
(E) 33.3%
20 Sep 2023, 23:46
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RenB
We can plot the information on a 2 * 2 matrix and solve the question. The detailed solution to the question is shown below -
Attachment:
Screenshot 2023-09-21 121453.jpg [ 83.89 KiB | Viewed 8690 times ]
Option E
23 Sep 2023, 12:36
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RenB
Really good question.
Let's take 150 as total shipments. T=150.
S = Stained (salmonella)
SR1 = Stained (salmonella) Rejected
SR2 = Stained (salmonella) Not Rejected
U = Unstained
UR1 = Unstained (salmonella) Rejected
UR2 = Unstained (salmonella) Not Rejected
Total = 150
Stained = \(\frac{1}{5}*150\) = 30
Unstained = 120
80% of S is rejected.
SR1 = 24.
SR2 = 6.
We know that U = 120.
So, UR1 = x and UR2 = 120-x
Given: the total number of rejected shipments is equal to one-third of the number of untainted shipments that are NOT rejected.
Translating to the equation:
SR1 + UR1 = \(\frac{1}{3}*UR2\)
24 + x = \(\frac{1}{3}*(120-x)\)
x = 12
Question is asking for: \(\frac{x}{SR1+US1}\)
\(\frac{12}{24+12}\) = \(\frac{1}{3}\)
Answer = E: 33.3%
