Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2212:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 1612:00 PM EDT
-11:59 PM EDT
You’re first to know: Save $200 on GMAT prep starting tomorrow, 4/13. Get 6 official practice tests and study with real questions. Be ready to save!
Apr 2301:30 AM EDT
-02:30 AM EDT
Struggling with GMAT Verbal as a non-native speaker? Harsh improved his score from 595 to 695 in just 45 days—and scored a 99 %ile in Verbal (V88)! Learn how smart strategy, clarity, and guided prep helped him gain 100 points.
Apr 2308:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
18 Mar 2024, 02:58
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
61% (02:29) correct
39%
(02:34)
wrong
based on 28
sessions
History
Date
Time
Result
Not Attempted Yet
Two cars, each moving at their respective constant speeds, depart simultaneously from points A and B towards each other. After passing each other, the car from point A reaches point B in 25 minutes, while the car from point B reaches point A in 36 minutes. How many minutes did it take for the faster car to cover the entire distance between the two points?
A. 44 minutes
B. 45 minutes
C. 50 minutes
D. 55 minutes
E. 60 minutes
A. 44 minutes
B. 45 minutes
C. 50 minutes
D. 55 minutes
E. 60 minutes
18 Mar 2024, 02:58
Kudos
Bookmarks
Official Solution:
Two cars, each moving at their respective constant speeds, depart simultaneously from points A and B towards each other. After passing each other, the car from point A reaches point B in 25 minutes, while the car from point B reaches point A in 36 minutes. How many minutes did it take for the faster car to cover the entire distance between the two points?
A. 44 minutes
B. 45 minutes
C. 50 minutes
D. 55 minutes
E. 60 minutes
Since the cars departed simultaneously and after meeting, the car from point A reached point B in less time than the car from point B took to reach point A, it's evident that the car from point A is faster.
Assuming they met after \(t\) minutes, then the car from A spent 25 minutes covering the same distance the car from B covered in \(t\) minutes. Since they travel at constant speeds, the ratio of their speeds would be equal to the reciprocal of the ratio of their times: the ratio of speeds of A to that of B = \(\frac{t}{25}\). For instance, if one car took \(t\) minutes to cover 10 kilometers, and another took 25 minutes to cover the same distance, then the ratio of the speed of the first car to that of the second car would be \(\frac{(\frac{10}{t})}{(\frac{10}{25})}=\frac{25}{t}\).
Similarly, since the car from A spent \(t\) minutes covering the same distance the car from B covered in 36 minutes, we'd have the ratio of speeds of A to that of B = \(\frac{36}{t}\).
Equating these two gives: \(\frac{t}{25} = \frac{36}{t}\), which yields \(t^2 = 25 * 36\), and finally, \(t = 5 * 6 = 30\) minutes.
Therefore, the faster car, the one from point A, took \(t + 25 = 30 + 25 = 55\) minutes to cover the entire distance between the two points.
Answer: D
Two cars, each moving at their respective constant speeds, depart simultaneously from points A and B towards each other. After passing each other, the car from point A reaches point B in 25 minutes, while the car from point B reaches point A in 36 minutes. How many minutes did it take for the faster car to cover the entire distance between the two points?
A. 44 minutes
B. 45 minutes
C. 50 minutes
D. 55 minutes
E. 60 minutes
Since the cars departed simultaneously and after meeting, the car from point A reached point B in less time than the car from point B took to reach point A, it's evident that the car from point A is faster.
Assuming they met after \(t\) minutes, then the car from A spent 25 minutes covering the same distance the car from B covered in \(t\) minutes. Since they travel at constant speeds, the ratio of their speeds would be equal to the reciprocal of the ratio of their times: the ratio of speeds of A to that of B = \(\frac{t}{25}\). For instance, if one car took \(t\) minutes to cover 10 kilometers, and another took 25 minutes to cover the same distance, then the ratio of the speed of the first car to that of the second car would be \(\frac{(\frac{10}{t})}{(\frac{10}{25})}=\frac{25}{t}\).
Similarly, since the car from A spent \(t\) minutes covering the same distance the car from B covered in 36 minutes, we'd have the ratio of speeds of A to that of B = \(\frac{36}{t}\).
Equating these two gives: \(\frac{t}{25} = \frac{36}{t}\), which yields \(t^2 = 25 * 36\), and finally, \(t = 5 * 6 = 30\) minutes.
Therefore, the faster car, the one from point A, took \(t + 25 = 30 + 25 = 55\) minutes to cover the entire distance between the two points.
Answer: D
02 Dec 2024, 18:49
Kudos
Bookmarks
The following helped me understand the problem
Sa = Speed of A
Sb = Speed of B
t = time until they met
We can equal the distances before meet up and after meet up
(1) Sa*25min = t*Sb (Distance for A to arrive to point B after meet up = Distance for B to reach the meeting point)
(2) Sa*t=36min*Sb (Distance for A to reach the meeting point = Distance for B to arrive to point A after meet up )
Then (1) / (2) and solve fot t - Sa and Sb cancel out.
Sa = Speed of A
Sb = Speed of B
t = time until they met
We can equal the distances before meet up and after meet up
(1) Sa*25min = t*Sb (Distance for A to arrive to point B after meet up = Distance for B to reach the meeting point)
(2) Sa*t=36min*Sb (Distance for A to reach the meeting point = Distance for B to arrive to point A after meet up )
Then (1) / (2) and solve fot t - Sa and Sb cancel out.
