To determine if Emily spent more than the median amount at any of the five restaurants, let's analyze the information given in each statement separately and then together.
Statement (1) AnalysisEmily spent the same total amount at any three of the five restaurants.
Let's denote the amounts Emily spent at the five restaurants as
A,B,C,D,E such that A≤B≤C≤D≤E. The median amount spent is C.
From statement (1), the total amount spent at any three restaurants is the same. This implies the sum of any three amounts from
A,B,C,D,E is equal. Let's denote this sum as S.
Therefore, we can write:
A+B+C=S
A+B+D=S
A+B+E=S
A+C+D=S
A+C+E=S
A+D+E=S
B+C+D=S
B+C+E=S
B+D+E=S
C+D+E=S
From this, we can infer that
A,B,C,D,E must be equal because if the total of any three amounts is the same, it means each amount must be equal.
So, A=B=C=D=E.
Since all amounts are equal, the median amount C is equal to any of the amounts Emily spent, so Emily did not spend more than the median amount at any restaurant.
Therefore,
statement (1) alone is sufficient to answer the question.Statement (2) AnalysisEmily did not spend less than the average (arithmetic mean) amount at any of the restaurants.
The average amount spent is (A+B+C+D+E)5
Since Emily did not spend less than the average amount at any restaurant, it implies:
A≥ (A+B+C+D+E)/5
B≥ (A+B+C+D+E)/5
C≥ (A+B+C+D+E)/5
D≥ (A+B+C+D+E)/5
E≥ (A+B+C+D+E)/5
For all the above inequalities to hold, all amounts A,B,C,D,E must be equal to the average amount.
This is because if any one of them were less than the average, the corresponding inequality would not hold.
Since all amounts are equal, the median amount C is equal to any of the amounts Emily spent, so Emily did not spend more than the median amount at any restaurant.
Therefore, statement (2) alone is sufficient to answer the question.
Combining Both Statements
Since both statements alone are sufficient, there is no need to combine them.
The correct answer is: D