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11 Apr 2025, 00:30
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Difficulty:
45%
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Question Stats:
70% (02:32) correct
30%
(03:05)
wrong
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Two pipes, A and B, can fill a tank in 24 minutes and 32 minutes respectively. If both pipes are opened simultaneously, after how many minutes should pipe B be closed so that the tank is completely filled in 18 minutes?
(A) 6
(B) 8
(C) 10
(D) 11
(E) 13
(A) 6
(B) 8
(C) 10
(D) 11
(E) 13
11 Apr 2025, 00:38
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Ra = 1/24
Rb = 1/32
Rab = 1/24 + 1/32 = 7/96
Let x be the mins for which both work
7/96 * x + 1/24 ( (18-x) = 1
7x/96 + 3/4 -x/24 = 1
(7x - 4x)/96 = 1/4
3x = 24
x = 8
Rb = 1/32
Rab = 1/24 + 1/32 = 7/96
Let x be the mins for which both work
7/96 * x + 1/24 ( (18-x) = 1
7x/96 + 3/4 -x/24 = 1
(7x - 4x)/96 = 1/4
3x = 24
x = 8
Bunuel
11 Apr 2025, 02:47
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Bunuel
LCM of 24 and 32 minutes = 96 units . Let this value be the capacity of the tank.
Efficiency of pipe A = 96/24 = 4
Efficiency of pipe B = 96/32 = 3
Given the tank is filled in 18 minutes.
To find : after how many minutes should pipe B be closed so that the tank is completely filled in 18 minutes?
so, pipe A operates for 18 mins = 18* 4 = 72 units.
remaining units = 96 - 72 = 24 units.
This 24 units is filled by pipe B.
24 = 3* t.
t = 8 . Pipe B operates for 8 mins. After 8 mins pipe B has to be closed.
