I have an alternative here, though it can be longer and more mathematical, but I feel that it's better than making cases where I usually make mistakes.
Let the consecutive even integers be x, x+2, x+4, ... so on (with n terms)
Tricky part is to find the last term, as here it will be x+ (2n -2)
Second term (n=2) which is x+ 2*2 -2 = x+2
This will hold true for all values in the sequence.
We need to find the last term, i.e. x+2n-2 ..... Final Value
Thus, we need both n and x values.
The average is 35. n must be even as all values in the sequence are even, and an odd mean implies an even number of terms. Using the formula for Average -
(x+x+2+,...+x+2n-2)/n = 35 .... Eq 1
(1) The difference between the highest and lowest scores received by the students was 22 points.
x+2n-2 - x = 22
n = 12
Using the value of n in Eq 1, we can find x and use to calc the final value. (No need to solve anything)
(2) The lowest score received by a student was 24.
x = 24
Using this value of x in Eq 1, we can find value of n and use to calc the final value. (No need to solve anything)
Thus,
D