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Bunuel
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Bunuel
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I like the solution - it’s helpful.
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Bunuel : Can I say that average = (Low + high)/2 for evenly spaced ordered set ?
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Bunuel : Can I say that average = (Low + high)/2 for evenly spaced ordered set ?

Yes, for an evenly spaced ordered set the average equals the median and both equal (lowest term + highest term)/2. This holds because in an evenly spaced set, terms are symmetric around the midpoint.
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This is a great question that’s helpful for learning. This is a very cool question!
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This is a great question that’s helpful for learning. This is a very cool question!

Glad you liked it! Here’s another similar one from the GMAT Club Tests (avoid it if you’re currently taking the tests, as it may affect your score): https://gmatclub.com/forum/m40-444408.html
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I like the solution - it’s helpful.
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I have an alternative here, though it can be longer and more mathematical, but I feel that it's better than making cases where I usually make mistakes.

Let the consecutive even integers be x, x+2, x+4, ... so on (with n terms)
Tricky part is to find the last term, as here it will be x+ (2n -2)
Second term (n=2) which is x+ 2*2 -2 = x+2
This will hold true for all values in the sequence.

We need to find the last term, i.e. x+2n-2 ..... Final Value
Thus, we need both n and x values.

The average is 35. n must be even as all values in the sequence are even, and an odd mean implies an even number of terms. Using the formula for Average -
(x+x+2+,...+x+2n-2)/n = 35 .... Eq 1

(1) The difference between the highest and lowest scores received by the students was 22 points.
x+2n-2 - x = 22
n = 12
Using the value of n in Eq 1, we can find x and use to calc the final value. (No need to solve anything)

(2) The lowest score received by a student was 24.
x = 24
Using this value of x in Eq 1, we can find value of n and use to calc the final value. (No need to solve anything)

Thus, D
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