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15 Dec 2025, 14:51
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The cyclist travels a speed of 3 min / mile. This means they travel 1/3 miles in 1 min. So we can calculate that in the 48 minutes until they must return home they can cover 48 min x 1/3 miles = 16 miles. If they are already 10 miles away from home, then they can cycle 3 miles before they must turn back. This is because after 3 miles, they have traveled 13 miles away from home, and they must travel 16-3= 13 miles to return home. So the answer is B. 3 I believe.
Bunuel
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15 Dec 2025, 15:23
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Speed = 3 min/mile
So, in 48 minutes, the cyclist can cover 48/3 = 16 miles
Let the add. distance that cyclist covers = x
Distance to cover on return trip = 10+x
Total distance that cyclist covers after 10pm = x + (10+x) = 2x+10
2x+10 = 16
2x=6
x=3
So, in 48 minutes, the cyclist can cover 48/3 = 16 miles
Let the add. distance that cyclist covers = x
Distance to cover on return trip = 10+x
Total distance that cyclist covers after 10pm = x + (10+x) = 2x+10
2x+10 = 16
2x=6
x=3
Bunuel
15 Dec 2025, 15:26
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Answer choice B.
3 min/mile = 20 MPH
Total Travel time is 48 minutes 48 minutes / 60 minutes per hour = 4/5 of an hour
4/5 hours * 20 MPH = 16 miles, the maximum distance that can be traveled.
Cyclist starts 10 miles from home, wants to continuing riding then turn back and return home.
We can understand the additonal distance ridden as X. Distance from home before turning around will be 10 + x.
His trip return will be X + 10 + X = 16 | 2x + 10 = 16 | 2x = 6 | x =3 additional miles
Alternatively,
3 minutes / mile = 1/3 miles Miles Per Minute (MPM)
1/3 MPM * 48 minutes = 16 miles can be traveled
Must ride at least 10 miles back home
6 miles is left to be traveld, away from and back to starting point | 10 --> X & X --> 10 | 2x = 6 | x = 3
Sorry for any spelling mistakes... I suck at spelling. Thankfully that's not on the GMAT Focus
3 min/mile = 20 MPH
Total Travel time is 48 minutes 48 minutes / 60 minutes per hour = 4/5 of an hour
4/5 hours * 20 MPH = 16 miles, the maximum distance that can be traveled.
Cyclist starts 10 miles from home, wants to continuing riding then turn back and return home.
We can understand the additonal distance ridden as X. Distance from home before turning around will be 10 + x.
His trip return will be X + 10 + X = 16 | 2x + 10 = 16 | 2x = 6 | x =3 additional miles
Alternatively,
3 minutes / mile = 1/3 miles Miles Per Minute (MPM)
1/3 MPM * 48 minutes = 16 miles can be traveled
Must ride at least 10 miles back home
6 miles is left to be traveld, away from and back to starting point | 10 --> X & X --> 10 | 2x = 6 | x = 3
Sorry for any spelling mistakes... I suck at spelling. Thankfully that's not on the GMAT Focus
Bunuel
