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Let the fixed percentage rate per hour be r%

At 10 AM
Population of bacteria = 8000

At 7 PM (9 hours later)
Population of bacteria \(= 8000(1+r%)^9 = 64000\)
\((1+r%)^9 = 64000/8000 = 8 = k^9\) ; where k = 1+r%
\(k = (2^3)^{1/9} = 2^{1/3}\)

Let us assume that t hour after 10 AM: -
Population = 256000
With reference to population at 10 AM
8000*k^t = 256000
\(k^t = \frac{256000}{8000} = 32 = 2^5 = (2^{1/3})^15 = k^15\)
t = 15 hours

15 hours after 10 AM
Time = 1 AM of the next day

IMO E
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Bunuel
A culture of bacteria had a population of 8,000 at 10 AM. The population grew at a fixed percentage rate per hour and reached 64,000 at 7 PM on the same day. If the population continues to grow at that same rate, at what time will the population reach 256,000?

A. 9 PM of the same day
B. 10 PM of the same day
C. 12 AM of the next day
D. 12:30 AM of the next day
E. 1 AM of the next day

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10 AM - 7 PM = 9 Hrs.
8000.(r^9)=64000
r^9=8=2^3
r=2^(1/3)
So the population doubles every 3 Hrs.
256000=64000*4=64000*2^2
Each doubling takes 3 Hrs, so two doublings = 3*2 = 6
7PM+6hrs = 1 AM (next day) (OPTION E).
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Take doubling of population.

8000 -> 16000 -> 32000 -> 64000
Population doubled 3 times in 9 hours, i.e. it doubles every 3 hours.

Given population 64000 -> 128000 -> 256000
The population doubled 2 times, therefore it mast have taken 3hrs x 2 times = 6 hours

7 PM to 1 AM

Hence, Answer is option E
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A culture of bacteria had a population of 8,000 at 10 AM. The population grew at a fixed percentage rate per hour and reached 64,000 at 7 PM on the same day. If the population continues to grow at that same rate, at what time will the population reach 256,000?

A. 9 PM of the same day
B. 10 PM of the same day
C. 12 AM of the next day
D. 12:30 AM of the next day
E. 1 AM of the next day

at 10 am its 8000
and at 7PM its 64,000
in 9 hours duration it has increased to 8 times its value
8= 2^3
rate be r
2^3 = r^9
r= 2^(1/3)

256000= 8000 * (2^1/3) t
32= (2^1/3)t
2^5 =(2^1/3)t
5= 1/3 *t
t= 15 hours
which will be 1 am next day
OPTION E is correct
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time elapsed 10am to 7pm = 9hrs
population growth 8000 to 64000
64000/8000=8 2^3

growth rate hourly
P(t)=P0Xr^t
P0=8000
P(9)=64000
t=9hrs
64000=8000xr^9
8=r^9
r=8^1/9 hourly growth rate
time from 10am until pp is 256000
256000=8000Xr^t2
32=r^t2
32=8^t2/9

express both sides based on 2
2^5=(2^3)^T2/9
2^5=2^3t2/9
2^5=2t2/3

5=t2/3
t2=15hrs
10am+15hrs
1 AM of the next day
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From 10 am to 7 pm is 9 hours.
The population went from 8000 to 64000 in 9 hours
64000/8000=8
Means the population became 8 times larger in 9 hours.
8=2*2*2 =2^(1/3)
The population is doubling every 3 hours
10 am = 8000
1 pm = 16000
4 pm =32000
7 pm = 64000.....
10 pm= 128000
1 am next day = 256000
The population will reach 256000 at 1 AM next morning

E
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Bunuel
A culture of bacteria had a population of 8,000 at 10 AM. The population grew at a fixed percentage rate per hour and reached 64,000 at 7 PM on the same day. If the population continues to grow at that same rate, at what time will the population reach 256,000?

A. 9 PM of the same day
B. 10 PM of the same day
C. 12 AM of the next day
D. 12:30 AM of the next day
E. 1 AM of the next day

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64k = 8k * r^9
r^9 = 8

r = 2^(1/3)

now for calculating 256000
r^h = 256/8 = 32
plugging in r = 2^(1/3)
we get h = 15

so answer is 1 am
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Bunuel
A culture of bacteria had a population of 8,000 at 10 AM. The population grew at a fixed percentage rate per hour and reached 64,000 at 7 PM on the same day. If the population continues to grow at that same rate, at what time will the population reach 256,000?

A. 9 PM of the same day
B. 10 PM of the same day
C. 12 AM of the next day
D. 12:30 AM of the next day
E. 1 AM of the next day

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for every hour multiplies by r rate. From 10am to 7pm i.e. for 9 hours
Culture at 7pm = 8000(rˆ9) = 64000
rˆ9 = 8
or rˆ3 = 2 or r= 2ˆ(1/3)

8000(rˆt) = 256000
2ˆ(t/3)= 32 = 2ˆ5
or t/3 = 5 or t=15.
15 hours from 10am will be 1am of next day.
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10AM population is 8000.
7 PM The population is 64000.
Time difference is 9 hours.

If we see the growth rate = 64000/8000 = 8 = 2^3 (Doubled three times)

In 9 hours the population doubled three times that means it doubled every 3 hours.

If we check how much time it will need to reach 256000: 256000/64000 = 4 = 2^2.

It will double twice which means in another 6 hours.
Add 6 hours to 7 PM we get 1AM next day.
Ans : E.


Bunuel
A culture of bacteria had a population of 8,000 at 10 AM. The population grew at a fixed percentage rate per hour and reached 64,000 at 7 PM on the same day. If the population continues to grow at that same rate, at what time will the population reach 256,000?

A. 9 PM of the same day
B. 10 PM of the same day
C. 12 AM of the next day
D. 12:30 AM of the next day
E. 1 AM of the next day

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We are given that population grows at a fixed percent rate. We can take the rate as x.

Therefore, 8000(1+x/100)^9 = 64000 as there are 8 time periods between 10am and 7pm

(1+x/100)^9= 8

Taking cube root on both sides,

(1+x/100)^3=2

We are to find n where 8000(1+x/100)^n = 256000
(1+x/100)^n = 32 = 2^5

(1+x/100)^15 = 2^5

15 time periods from 10am correspond to 1am next day.

Therefore, Option E
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The bacteria grows at a fixed rate every hour, this means that if at 10am the amount is 8 thousands, at 11am the amount will be 8*n, at 12pm 8*n*n=8*n^2, and so on.

At 7pm (after 9 hours) the amount of bacteria is 8*n^9.
if 8*n^9 = 64
n^9 = 8
n^9 = 2^3
n = 2^(1/3)

8*n^x = 256
n^x = 32
x = 15
15 hours must pass from when the bacteria is 8000 (which is at 10am, so if 15 hours must pass, it means the bacteria reaches 256 at 1am the next day).

answer E
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At 10 am = population is 8000 and at 7pm = population is 64000
So In 9hrs, it grew 8 times i.e 2 times in every 3 hrs

So at 10pm same = population is 128000
And at 1am next day = population is 256000

Option E
Bunuel
A culture of bacteria had a population of 8,000 at 10 AM. The population grew at a fixed percentage rate per hour and reached 64,000 at 7 PM on the same day. If the population continues to grow at that same rate, at what time will the population reach 256,000?

A. 9 PM of the same day
B. 10 PM of the same day
C. 12 AM of the next day
D. 12:30 AM of the next day
E. 1 AM of the next day

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Assume rate is r % per hour hence problem becomes like compound interest 64000 = 8000(1 + r/100)^9 since 10 AM to 7 PM is 9 hours. Hence (1 + r/100) = 8^(1/9) ----- equation 1. Now let it takes n hours in becoming 256000 from 8000 so 256000 = 8000(1 + r/100)^n ---> 32 = (1 + r/100)^n ----> using equation 1, 32 = 8^(n/9) ---> 2^5 = 2^(n/3)----> n = 15 hours so after 10 AM 15 hours gives 1 AM of next day. Ans option E.
Bunuel
A culture of bacteria had a population of 8,000 at 10 AM. The population grew at a fixed percentage rate per hour and reached 64,000 at 7 PM on the same day. If the population continues to grow at that same rate, at what time will the population reach 256,000?

A. 9 PM of the same day
B. 10 PM of the same day
C. 12 AM of the next day
D. 12:30 AM of the next day
E. 1 AM of the next day

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64000=8000*\(r^9\)
\(r^9\) = 8

so, 8 times in 9 hrs.
so doubling time 3hrs. so 4 more times in 6 hrs.
total 15 hrs
10 AM +15 hrs = 1 AM next day

Ans E
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assume the rate of growth as X%
and a being the difference in time from 10Am to 7PM:

So I can write the equation for growth as it is same as compounding the value so:
8000(1 + x/100)^a = 64000

Since total time taken is 9 hrs so a = 9 for 8k to 16k
so solving above equation will give
(1+x/100)^9 = 2^3
hence (1+X/100)^3 = 2 --(1)

Now I want to calculate
8000(1+x/100)^b = 256000

so (1+x/100)^b = 2^5
so from 1
(1+x/100)^b = (1+x/100)^15

hence b = 15hrs

Therefore 1AM of next day
Hence (E)
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Bunuel
A culture of bacteria had a population of 8,000 at 10 AM. The population grew at a fixed percentage rate per hour and reached 64,000 at 7 PM on the same day. If the population continues to grow at that same rate, at what time will the population reach 256,000?

A. 9 PM of the same day
B. 10 PM of the same day
C. 12 AM of the next day
D. 12:30 AM of the next day
E. 1 AM of the next day

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The population of bacteria was 8000 at 10 AM.

They grew at a fixed percentage rate , and the population was 64000 at 7 PM.

Between 10 am to 7 pm , the number of hours is 9 hours.

During these 9 hours, the population multiplied by 8.

64000/8000 = 8

(3*3*3) hours = (2*2*2*) times

So, in 3 hours, the population has DOUBLED.

7 pm : 64000 ————> in 3 hours (10 pm) , the population became 64000*2 = 128000

So, in another 3 hours (1 AM), the population became 128000 * 2 = 256000.

So, the time taken to reach 256000 is 1 AM (Next Day).

Option E
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8000xr^9=64000
r is rate of increase per hour and 9 is the time take to reach population of 9 hrs
on simplyfying r=(2)^1/3

256000=8000x(r)^total
2^5=(2)^total/3
equating powers we get total=15

so after 15 hrs the population becomes 256000 answer is 1 AM next day
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