Last visit was: 04 Sep 2026, 00:24 It is currently 04 Sep 2026, 00:24
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
   1   2   3   4   5   6   7   
655-705 (Hard)|   Absolute Values|         
User avatar
twinkle2311
User avatar
Joined: 05 Nov 2021
Last visit: 03 Sep 2026
Posts: 211
Own Kudos:
246
 [1]
Given Kudos: 54
Location: India
Concentration: Finance, Real Estate
Schools: ISB '27 Wharton '27
GPA: 9.041
Schools: ISB '27 Wharton '27
Posts: 211
Kudos: 246
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:25
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
From | x-y | = y-x, we know that y-x must be +ve
Since x != y, this means y > x
Also, since y < 0, x must be -ve as well.

Now, solve each term :

x/|x| = -1 ( because x is -ve)
|-y|/(-y) = 1 ( because -y is +ve)
(x-y)/|y-x| = -1 (because y>x, |y-x| = y-x)
|xy|/(xy) = 1 (product of 2 -ve values is positive)

Total = -1 + 1 - 1 + 1 = 0

Ans : B
User avatar
Dipan0506
User avatar
Joined: 24 May 2021
Last visit: 27 Aug 2026
Posts: 88
Own Kudos:
14
Given Kudos: 7
Posts: 88
Kudos: 14
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:25
Kudos
Add Kudos
Bookmarks
Bookmark this Post
If |x-y|=y-x, xy, and y<0
User avatar
GaganB
User avatar
Joined: 30 Jan 2022
Last visit: 02 Sep 2026
Posts: 28
Own Kudos:
12
 [1]
Given Kudos: 29
Location: India
Schools: ESADE INSEAD Aug '27 ISB '27
GMAT Focus 1: 605 Q84 V82 DI74
Products:
GMAT Club Tests
Schools: ESADE INSEAD Aug '27 ISB '27
GMAT Focus 1: 605 Q84 V82 DI74
Posts: 28
Kudos: 12
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:26
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
|x-y| = -(x-y) is possible only when (x-y) <= 0 which implies either x = y or x < y. Since x \ne y, that means x < y. Coupled with y < 0, we get x < y < 0. Now take any values that fit this inequality. Let x = -2, y = -1 and plug it in the fractions given.

\frac {x}{|x|} = -1
\frac {|-y|}{-y} = 1
\frac {x-y}{|y-x|} = -1
\frac {|xy|}{xy} = -1

Ans = 0
Bunuel
If \(|x-y|=y-x\), \(x \ne y\), and \(y<0\), what is the value of \(\frac{x}{|x|}+\frac{|-y|}{-y}+\frac{x-y}{|y-x|}+\frac{|xy|}{xy}\)?

A. -2
B. 0
C. 1
D. 2
E. 4


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
Show more
User avatar
ShreyaMittal1609
User avatar
Joined: 05 Nov 2025
Last visit: 03 Sep 2026
Posts: 82
Own Kudos:
45
 [1]
Given Kudos: 208
GMAT Focus 1: 545 Q77 V77 DI77
Products:
My Reviews GMAT Club Tests Forum Quiz
GMAT Focus 1: 545 Q77 V77 DI77
Posts: 82
Kudos: 45
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:26
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
My answer is B). 0
Based on |x-y|= y-x; we get
y-x>=0
y>=x. But question tells that x is not equal to y and y is negative.
We can conclude condition: y>x, where both x and y are negative numbers and y is a smaller negative say If x is -2 then y can be -1
Substituting x as -2 and y as -1 in the equation, we get= -1+1-1+1=0
Bunuel
If \(|x-y|=y-x\), \(x \ne y\), and \(y<0\), what is the value of \(\frac{x}{|x|}+\frac{|-y|}{-y}+\frac{x-y}{|y-x|}+\frac{|xy|}{xy}\)?

A. -2
B. 0
C. 1
D. 2
E. 4


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
Show more
User avatar
rockstar09rulez
User avatar
Joined: 30 Sep 2023
Last visit: 26 Aug 2026
Posts: 43
Own Kudos:
25
 [1]
Given Kudos: 74
Location: United States (CA)
Concentration: Technology, Finance
Products:
GMAT Club Tests
Posts: 43
Kudos: 25
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:28
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
|x-y| = y-x means the modulus opens with a negative sign, which means x-y < 0, meaning x < y
Now since y < 0, x is also less than 0 since x < y
So both x and y are negative

With this in mind, we resolve all modulus values in the expression
x/|x| -> mod x opens as -x, so -1

|-y|/-y -> |y|/-y, mod y opens as -y, so 1

x-y/|y-x| -> x-y < 0 , so y-x > 0, so mod opens as y-x, so value is -1

|xy|/xy -> since xy both negative, xy will be positive, so mod opens as xy, hence value is 1

Adding all 4, we get 0, hence B)
User avatar
RDM42
User avatar
Joined: 20 Jan 2025
Last visit: 24 Aug 2026
Posts: 464
Own Kudos:
328
Given Kudos: 29
Posts: 464
Kudos: 328
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:32
Kudos
Add Kudos
Bookmarks
Bookmark this Post
|x-y|=y-x
Then, x-y<0. x<y
x<y<0.
Let, x=-2, y=-1

(-2)/2 + 1/1 + (-2+1)/|-1+2| + 2/2
= -1+1-1+1= 0

B
User avatar
tm28
User avatar
Joined: 06 Jun 2021
Last visit: 26 Aug 2026
Posts: 10
Own Kudos:
8
 [1]
Given Kudos: 64
Posts: 10
Kudos: 8
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:35
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
in order to satisfy the given function condition, let x=-4 and y=-3 since y<0 and x not equal to y. Putting the given values in final equation, the answer is 0.
Bunuel
If \(|x-y|=y-x\), \(x \ne y\), and \(y<0\), what is the value of \(\frac{x}{|x|}+\frac{|-y|}{-y}+\frac{x-y}{|y-x|}+\frac{|xy|}{xy}\)?

A. -2
B. 0
C. 1
D. 2
E. 4


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
Show more
User avatar
GlassChamp
User avatar
Joined: 05 Jun 2026
Last visit: 23 Aug 2026
Posts: 20
Own Kudos:
15
 [1]
Given Kudos: 1
Location: India
Schools: ISB '27 Kellogg
GPA: 7.7
Schools: ISB '27 Kellogg
Posts: 20
Kudos: 15
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:35
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Given,
\(|x-y|=y-x\)
Opening the modulus;

Case 1: Let (x-y)>0
\(|x-y|=y-x\) becomes (x-y) = (y-x)
or, 2x=2y
or, x=y
Not possible (Since given in the question that \(x \ne y\))

Case 2: (x-y) <0
\(|x-y| = y-x \) becomes -(x-y)= (y-x)
or, y-x = y-x
or, 0 = 0
Hence, true for all the values of x & y.
Thus, x-y < 0
or, x < y
Also, since y<0 (this means x is also negative and having more magnitude)

Now, to easily solve the given equation, we can assume any negative values of x & y ( since the case 2 is valid for every x & y)
Let, y= -1 and x =-2
Then the equation becomes:
\( \frac {-2}{|-2|} + \frac {|-(-1)|}{-(-1)} + \frac {-2-(-1)}{|-1-(-2)|} + \frac {|-2 * -1|}{-2 * -1}\)
which simplifies to:
-1 + 1 + (-1) + 1 = 0
Hence the final answer is B. 0
User avatar
MANASH94
User avatar
Joined: 25 Jun 2025
Last visit: 03 Sep 2026
Posts: 165
Own Kudos:
121
 [1]
Given Kudos: 27
Location: India
Schools: IIM IIM ISB
GMAT Focus 1: 525 Q80 V76 DI72
GPA: 2.9
Products:
GMAT Club Tests
Schools: IIM IIM ISB
GMAT Focus 1: 525 Q80 V76 DI72
Posts: 165
Kudos: 121
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:39
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
if |x-y| = y - x that means that x - y < 0.
We can say that x<y. Also given that y<0 we can assume just two numbers here.
say x = -2 and y = -1.
Put this in the expression and we get the expression as 0.
Ans B IMO.
Bunuel
If \(|x-y|=y-x\), \(x \ne y\), and \(y<0\), what is the value of \(\frac{x}{|x|}+\frac{|-y|}{-y}+\frac{x-y}{|y-x|}+\frac{|xy|}{xy}\)?

A. -2
B. 0
C. 1
D. 2
E. 4


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
Show more
User avatar
Saurav1408
User avatar
Joined: 26 Oct 2023
Last visit: 02 Sep 2026
Posts: 81
Own Kudos:
61
 [1]
Given Kudos: 287
Status:Active
Location: India
Products:
My Reviews
Posts: 81
Kudos: 61
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:42
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
In this question if we note that y is negative(GIVEN) and |x-y| = y - x. We could infer that 'x' shall be negative too because when we open the mod |x-y| it equates to y-x and y<0 so it would change the sign to '+' |x+y| and then in the result we get y-x. So x must be negative and smaller than 'y' to prove this below is the explanation too: x-y cannot be zero as x is not equal to y also y is negative. So x-y<0 which gives x<y.
Since y is negative so x<y<0
Not just replace the x with -x and y with -y.
The first term would be -1, second term would be 1, third term would be -1 and the last term would be 1.
When calculated it would equal to zero.

Let me know if there is any confusion
User avatar
BongBideshini
User avatar
Joined: 25 May 2021
Last visit: 03 Sep 2026
Posts: 390
Own Kudos:
239
Given Kudos: 137
Location: India
Concentration: Entrepreneurship, Marketing
Schools: HBS '27 Stanford '27 Wharton '27 Sloan '27
GPA: 3.8
WE:Engineering (Government)
Schools: HBS '27 Stanford '27 Wharton '27 Sloan '27
Posts: 390
Kudos: 239
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:43
Kudos
Add Kudos
Bookmarks
Bookmark this Post
|x-y|=y-x, then y-x>=0, but as y<0, we can say x<y<0

x/|x| + |-y|/|y| + (x-y)/|y-x| +|xy|/xy
= -1 + 1 + 1 + 1
2
Ans D
User avatar
imakriti07
User avatar
Joined: 05 Sep 2024
Last visit: 29 Aug 2026
Posts: 2
Own Kudos:
1
 [1]
Posts: 2
Kudos: 1
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:46
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
On solving
X/x=1
|-y|/-y= y/-y =-1
X-y/|y-x| = x-y/-(x-y) = -1
|xy|/xy= 1
1-1-1+1= 0
User avatar
KEETAN11
User avatar
Joined: 20 Apr 2026
Last visit: 24 Aug 2026
Posts: 18
Own Kudos:
17
 [1]
Given Kudos: 34
Posts: 18
Kudos: 17
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:48
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If \(|x-y|=y-x\), \(x \ne y\), and \(y<0\), what is the value of \(\frac{x}{|x|}+\frac{|-y|}{-y}+\frac{x-y}{|y-x|}+\frac{|xy|}{xy}\)?

A. -2
B. 0
C. 1
D. 2
E. 4


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
Show more
given that \(|x-y| = y-x \) , if this needs to be true then x-y < = 0
so x<=y
also given \(x \ne y\)
so x < y
given y<0
so x<y<0
both are negative,
\(\frac {x} {|x|}\)
x<0 , \(|x|= -x\)
so , \(\frac {x} {-x}\) = -1

\(\frac {|-y|} {-y}\)
y<0, -y>0
\(|-y|= -y\)
so, \(\frac {-y} {-y}\) = 1

\(\frac {x-y} {|y-x|}\)
since x<y, y-x is positive
so \(|y-x| = y-x\)
so, \(\frac {x-y} {y-x} = -1\)

\(\frac {|xy|} {xy}\)
since, x<0, y<0
xy>0
so, |xy| = xy
\(\frac {|xy|} {xy} = 1\)

-1+1+(-1) +1 = 0
B
User avatar
VenkataSai
User avatar
Joined: 21 Jul 2025
Last visit: 03 Sep 2026
Posts: 42
Own Kudos:
21
 [1]
Given Kudos: 19
GMAT Focus 1: 595 Q81 V80 DI78
Products:
My Reviews GMAT Club Tests
GMAT Focus 1: 595 Q81 V80 DI78
Posts: 42
Kudos: 21
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:48
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Given, |x-y| = y-x. This means y>x.
Also given y<0. Meaning x is also less than 0. thus both are negetive.
For the answer sake, let x=-4 and y=-2.
Hence the equation, considering absolute values becomes : -4/4 + 2/-(-2) + (-4-(-2))/|-2-(-4)| + |-2 X -4|/-2 X-4 = -1+1-1+1 = 0
Bunuel
If \(|x-y|=y-x\), \(x \ne y\), and \(y<0\), what is the value of \(\frac{x}{|x|}+\frac{|-y|}{-y}+\frac{x-y}{|y-x|}+\frac{|xy|}{xy}\)?

A. -2
B. 0
C. 1
D. 2
E. 4


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
Show more
User avatar
Sumimasen
User avatar
Joined: 21 Jan 2024
Last visit: 27 Jul 2026
Posts: 48
Own Kudos:
43
 [1]
Given Kudos: 13
Posts: 48
Kudos: 43
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:53
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
|x-y| = y-x, it means y>x and x is not equal to y as given in question statement itself.
Also, y<0 given. It means x is also <0.

Accordingly, x/|x| will be -1, |-y|/-y = 1, x-y/|y-x| = -1 and |xy|/xy = 1
-1+1-1+1 = 0

Ans. B
Bunuel
If \(|x-y|=y-x\), \(x \ne y\), and \(y<0\), what is the value of \(\frac{x}{|x|}+\frac{|-y|}{-y}+\frac{x-y}{|y-x|}+\frac{|xy|}{xy}\)?

A. -2
B. 0
C. 1
D. 2
E. 4


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
Show more
User avatar
DishaSaha
User avatar
Joined: 03 Nov 2024
Last visit: 30 Aug 2026
Posts: 64
Own Kudos:
49
 [1]
Given Kudos: 24
GMAT Focus 1: 555 Q81 V75 DI78
GMAT Focus 1: 555 Q81 V75 DI78
Posts: 64
Kudos: 49
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 09:59
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
|x-y|=y-x
.: x-y<0
.: x<y
we know, y<0
.: x<0
.: |x|/x=-1
|-y|/-y=-(-1)=1
|y-x|=|-1||x-y|=|x-y|
.: (x-y)/ |y-x|= -1
|xy|/xy=1 (Since, both x & y are negative)

.: -1+1-1+1=0
Ans is B.
Bunuel
If \(|x-y|=y-x\), \(x \ne y\), and \(y<0\), what is the value of \(\frac{x}{|x|}+\frac{|-y|}{-y}+\frac{x-y}{|y-x|}+\frac{|xy|}{xy}\)?

A. -2
B. 0
C. 1
D. 2
E. 4


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
Show more
User avatar
GoodKey
User avatar
Joined: 29 May 2026
Last visit: 03 Sep 2026
Posts: 42
Own Kudos:
36
Given Kudos: 3
Products:
GMAT Club Tests Forum Quiz
Posts: 42
Kudos: 36
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 10:01
Kudos
Add Kudos
Bookmarks
Bookmark this Post
From the given conditions we can figure out that y is negative as y < 0.
Also, since |x-y|=y-x, from this we can gather that x has to be negative since y-x needs to be a positive number for the equation to satisfy.

Thus:
1. x/|x| = -1
2. |-y|/-y = 1
3. (x-y)/|y-x| = 1
4. |xy|/xy = 1

Therefore, -1+1+1+1 = 2
Answer is (D)
User avatar
shivani1351
User avatar
Joined: 23 Apr 2021
Last visit: 02 Sep 2026
Posts: 178
Own Kudos:
126
 [1]
Given Kudos: 10
Posts: 178
Kudos: 126
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 10:11
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
As |x-y| = y-x, x-y < 0 (Using the property of modulus)
Thus, x < y, and since y < 0, x < 0
For simplification, let's use numbers in place of the variables x and y.
Let's assume y = -1 and x = -2 (Remember x needs to be smaller than y)

Now, let's solve for the individual components of the sum by individually, by using the above information:
x/|x| = -2/2 = -1
|-y|/-y = 1/1 = 1
x-y/|y-x| = -1/1 = -1
|xy|/xy = 2/2 = 1

Adding these all up, -1+1-1+1, we get the answer as 0.

Hence, the correct answer is Option B - 1.

Hope this helps! :)
User avatar
Stiwari4001
User avatar
Joined: 25 Jul 2025
Last visit: 02 Sep 2026
Posts: 28
Own Kudos:
23
 [1]
Given Kudos: 17
Posts: 28
Kudos: 23
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 10:16
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Not sure if this is the smartest or the best method but here goes:

We know that |x-y| = y-x ---------(1) (y is negative and x is not equal to y)

Since the question is in terms of x and y, it would help to know the sign of x.

If x is zero OR +ve,
We will get RHS = -ve in (1) which is not possilble (as RHS is an abosolute value)
Therefore, x<0 ---------- (2)

Now that we know the sign, it can help to know a relation between magnitude of x and y

if |x| < |y|
It will again give RHS as -ve
(since we've established x & y both are -ve, the equation will essentially become -|y| + |x|. And if we remove a smaller number from y than itself, RHS will stay -ve)

Therefore, we can deduce that |x| > |y| ---------- (3)

Armed with (2) and (3), we attack the question. Let's look at each term individually
x/|x| = -1 (since x<0, from (2)
|-y|/(-y) = +1 (since y<0)
(x-y)/|y-x| = -1 (since x&y<0; x-y=-(y-x) and we know from (1) that y-x is positive. Therefore, this term = -((y-x)/|y-x|)
|xy|/xy= +1 (since both x & y<0)

This gives us:
-1+1+(-1)+1
=0

Ans: B
User avatar
chasing725
User avatar
Joined: 22 Jun 2025
Last visit: 16 Aug 2026
Posts: 241
Own Kudos:
235
 [1]
Given Kudos: 6
Location: United States (OR)
Schools: Stanford
Schools: Stanford
Posts: 241
Kudos: 235
 [1]
GMAT Club World Cup 2026 (Day 2): If |x - y| = y - x, x y, and y < 0 07 Jul 2026, 10:22
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If \(|x-y|=y-x\), \(x \ne y\), and \(y<0\), what is the value of \(\frac{x}{|x|}+\frac{|-y|}{-y}+\frac{x-y}{|y-x|}+\frac{|xy|}{xy}\)?

A. -2
B. 0
C. 1
D. 2
E. 4


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
Show more

y - x > 0

y > x

x/|x| = -1

|-y|/-y = +1

(x-y)/|y-x| = -1

|xy| / xy = 1

-1 + 1 - 1 + 1 = 0

Option B
   1   2   3   4   5   6   7   
Moderator:
Bunuel
Math Expert
113112 posts