Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 2401:30 AM EDT
-01:30 AM EDT
Tejas studied hard but kept repeating the same mistakes. After 3 attempts at 645, a focused 4-week strategy helped him identify and fix what was holding him back—leading to a 695 with just 12–15 hours of study per week.
Sep 2408:00 AM EDT
-08:30 AM EDT
Meet Tuck at an informal student or staff-hosted coffee chat in a city near you!
Sep 2312:30 AM EDT
-01:30 AM EDT
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Sep 2601:00 PM EDT
-04:00 PM EDT
Top scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included. Class starts Saturdays Sept. 26, 2026 - Dec. 19, 2026, 1:00pm-4:00pm ES
Sep 2606:00 PM PDT
-07:00 PM PDT
Free- full-length test + 15 concept videos + 150+ short videos + study plan!
Sep 2911:00 AM EDT
-01:00 PM EDT
" Description: Top scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thur Sept. 29, 2026 - Dec. 3, 2026, 11:00am-1:00pm EST
Oct 0107:00 AM BST
-08:00 AM GMT
Welcome to the GMAT Club's Free Interview Prep Event for Top MBA Programs! Buy tickets - Virtual series that’s all set to equip you to -excel in your MBA interviews.
08 Jul 2026, 14:52
Kudos
Bookmarks
Three buses leave Riverton and travel along the same route toward Lakeview. Bus 1 leaves first and travels at a constant speed of 50 km/h. Bus 2 leaves Riverton 6 hours after Bus 1 and travels at a constant speed of 80 km/h. Bus 3 also leaves Riverton after Bus 1 and travels at a constant speed of 100 km/h. If Bus 2 and Bus 3 catch up to Bus 1 at the same time, how many hours after Bus 1 leaves does Bus 3 leave?
A. 2
B. 6
C. 8
D. 10
E. 16
We know that after 6 hours, but one will be 300 km away (50 km/h x 6 hours), and bus 2 is just leaving. Bus 2 travels at 80 km/h, so it will gain 30 km/h on bus one since 80-50 km/h =30. This means it will take take 10 hours for bus 2 to catch up to bus 1, having traveled a total of 800 miles. 50 km/h x16 hrs= 80 km/h x10 hrs.
To travel the same 800 miles, it will take a total 8 hrs since 800 km/100 km per h is 8. Since bus 1 takes a total of 16 hrs, this means bus 3 leaves 8 hrs afterwards. Option c.
A. 2
B. 6
C. 8
D. 10
E. 16
We know that after 6 hours, but one will be 300 km away (50 km/h x 6 hours), and bus 2 is just leaving. Bus 2 travels at 80 km/h, so it will gain 30 km/h on bus one since 80-50 km/h =30. This means it will take take 10 hours for bus 2 to catch up to bus 1, having traveled a total of 800 miles. 50 km/h x16 hrs= 80 km/h x10 hrs.
To travel the same 800 miles, it will take a total 8 hrs since 800 km/100 km per h is 8. Since bus 1 takes a total of 16 hrs, this means bus 3 leaves 8 hrs afterwards. Option c.
⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
08 Jul 2026, 14:57
Kudos
Bookmarks
B1 travels 300 km before B2 start
B2 is 30km/h faster so it takes 10 hours to cover that B1 head start. Then total time is 10+6 = 16 hours
while total B1 distance = 50 x 16 = 800km
which B3 can cover in 8 hours, so it can give B1 a 8 hour head start
B2 is 30km/h faster so it takes 10 hours to cover that B1 head start. Then total time is 10+6 = 16 hours
while total B1 distance = 50 x 16 = 800km
which B3 can cover in 8 hours, so it can give B1 a 8 hour head start
08 Jul 2026, 15:28
Kudos
Bookmarks
For convenience purpose, I will call Buses as B1, B2, B3 in the order they are given.
B1 leaves and travels for 6 hours before B2 starts. Hence, by the time B2 leaves, B1 has already travelled 6x50=300.
Now, B2 has to cover 300km in order to catch up with B1.
Using relative speed formula we can find out how much time B2 took before it could catch up to B1.
————-> 300/80-50 = 10 hours.
At this point B3 has also caught up with B1. Now, B1 must have travelled 300km + (10x50)km=800 km
To travel 800km, time taken by B3 is going to be 800/100=8 hours.
And B1 has travelled 16 hours
That means 16-8=8 . B3 left 8 hours after B1 left.
B1 leaves and travels for 6 hours before B2 starts. Hence, by the time B2 leaves, B1 has already travelled 6x50=300.
Now, B2 has to cover 300km in order to catch up with B1.
Using relative speed formula we can find out how much time B2 took before it could catch up to B1.
————-> 300/80-50 = 10 hours.
At this point B3 has also caught up with B1. Now, B1 must have travelled 300km + (10x50)km=800 km
To travel 800km, time taken by B3 is going to be 800/100=8 hours.
And B1 has travelled 16 hours
That means 16-8=8 . B3 left 8 hours after B1 left.
