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10 Jul 2026, 06:20
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We have 6 interns a, b, c, d, e, f
Three groups G1, G2, & G3
G1 - oldest
G3 - youngest
we know
- b > d
- d > 3 siblings => b > d & all 3 siblings (b - definitely part of G1 & d definitely not part of G3)
- E not one of the siblings => a, c, f are siblings
Question G2 maybe but not G3 => d (Daria) we know definitely not G3 can be part of G2 or G1 depending on e's age
Any of the three groups - e - Elise
If e > b or d < e < b -> G1
if e < d but e > all siblings -> G2
if e < all siblings -> G3
Ans: Daria & Elise
Three groups G1, G2, & G3
G1 - oldest
G3 - youngest
we know
- b > d
- d > 3 siblings => b > d & all 3 siblings (b - definitely part of G1 & d definitely not part of G3)
- E not one of the siblings => a, c, f are siblings
Question G2 maybe but not G3 => d (Daria) we know definitely not G3 can be part of G2 or G1 depending on e's age
Any of the three groups - e - Elise
If e > b or d < e < b -> G1
if e < d but e > all siblings -> G2
if e < all siblings -> G3
Ans: Daria & Elise
Bunuel
10 Jul 2026, 06:33
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Lets break it down
Bram is oldest! always group 1
Daria and Elise can switch, but also Elise can be the most youngest
We get scenarios
BDE(ACF)
BED(ACF)
BD(ACF)E
ACF can be in any order
Notice Elise can fit in any of the groups.
And Group 2 but not Group 3 is satisfied by Daria.
Hence the relevant answers IMO
Bram is oldest! always group 1
Daria and Elise can switch, but also Elise can be the most youngest
We get scenarios
BDE(ACF)
BED(ACF)
BD(ACF)E
ACF can be in any order
Notice Elise can fit in any of the groups.
And Group 2 but not Group 3 is satisfied by Daria.
Hence the relevant answers IMO
10 Jul 2026, 06:38
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This was quite an interesting and fun problem. So according to the given facts, and data sets this is what can be ascertained.
I am simplifying each of their names as A,B,C,D,E and F respectively. We have the following information:
B>D
D> 3 siblings - say x,y,z for now.
E -> Not a sibling.
From this we can infer that E & D are not siblings since there are exactly 3 siblings. E is ruled out from the data set. And D > all 3 siblings so D also cannot be a sibling. And B > D which means B > x,y,z or all 3 siblings as well.
So we have:
Not Siblings - B, D, E
Siblings - A, C, F
Now the progression of ages:
B>D > A,C,F [Unclear who is older amongst the three]
Next with 'E' it is quite interesting. E can be the youngest, oldest or can slot in after B, D, A, C, F. E is the one that could fit anywhere and amongst all the 3 groups. Since though D > A,C,F it is nowhere given that E >= or <= A,C,F. So E could very well be A>E or C>E or F>E.
So how I have written it is as follows:
(E) > B > (E) > D > (E) > A (E), C (E), F (E) > (E)
Basically to highlight above that E could potentially slot in anywhere.
So far as question 1 - which could come in Group 2 but not in Group 3.
If we calculate the one that is constant to come in Group 2, it is A. Because wherever 'E' lands, A is always either No. 3 or No. 4 in the age denomination. Hence the answer to Question 1 is A.
So far as question 2, it is evident that E could end up at Group 1 as the oldest or second oldest or third, fourth, fifth or sixth. So E is answer to Question 2.
Other PS problems were challenging but this was fun!
I am simplifying each of their names as A,B,C,D,E and F respectively. We have the following information:
B>D
D> 3 siblings - say x,y,z for now.
E -> Not a sibling.
From this we can infer that E & D are not siblings since there are exactly 3 siblings. E is ruled out from the data set. And D > all 3 siblings so D also cannot be a sibling. And B > D which means B > x,y,z or all 3 siblings as well.
So we have:
Not Siblings - B, D, E
Siblings - A, C, F
Now the progression of ages:
B>D > A,C,F [Unclear who is older amongst the three]
Next with 'E' it is quite interesting. E can be the youngest, oldest or can slot in after B, D, A, C, F. E is the one that could fit anywhere and amongst all the 3 groups. Since though D > A,C,F it is nowhere given that E >= or <= A,C,F. So E could very well be A>E or C>E or F>E.
So how I have written it is as follows:
(E) > B > (E) > D > (E) > A (E), C (E), F (E) > (E)
Basically to highlight above that E could potentially slot in anywhere.
So far as question 1 - which could come in Group 2 but not in Group 3.
If we calculate the one that is constant to come in Group 2, it is A. Because wherever 'E' lands, A is always either No. 3 or No. 4 in the age denomination. Hence the answer to Question 1 is A.
So far as question 2, it is evident that E could end up at Group 1 as the oldest or second oldest or third, fourth, fifth or sixth. So E is answer to Question 2.
Other PS problems were challenging but this was fun!
