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GMAT Club World Cup 2026 (Day 4): A company is assigning 6 interns

1 2 3 4 5

Rishm

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09 Jul 2026, 12:38

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Elise can be any group, as she has no age written or younger or older. Also Daria is older to 3 siblings hence, she can never be in 3rd group but can be in 2. Hence this is our answer- Elise- Any group and Daria - 2 but not 3.

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09 Jul 2026, 12:57

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We are sure about
Age(Bram) >Age( Daria) > Age( 3 interns)
since Elise is not sibling, then Anya, Clara, and Felix are siblings)
Since Daria can't be group 3 and sibling can never be in gourp 1 then we have only one we have one option Elise, she can be anywhere in the above age line ( So any group) and based on Elise position Daria could be in group 2 if Age(Elise)> Age(Daria) but won't be in group 3 since she is elder than all 3 sibling so she won't be Least 3 youngest intern and won't be allocated to Group 3 .
So Daria can be in group 2 but never in Group 3 and Elise can be in any group.

Bunuel

A company is assigning 6 interns, Anya, Bram, Clara, Daria, Elise, and Felix, to 3 orientation groups based on age. The 2 oldest interns will be assigned to Group 1, the 2 youngest interns will be assigned to Group 3, and the remaining 2 interns will be assigned to Group 2. No two interns are the same age. Exactly 3 of the interns are siblings.

The following information is known:

• Bram is older than Daria.
• Daria is older than each of the 3 siblings.
• Elise is not one of the siblings.

Select for Group 2 but not Group 3 an intern who could be in Group 2 but could not be in Group 3, and select for Any Group an intern who could be in any one of the 3 groups. Make only two selections, one in each column.

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09 Jul 2026, 15:51

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Since D is older than all 3 siblings, she cannot be one of the siblings.

B is older than D, so he can't be a sibling either.

The argument mentioned that E is not a sibling. That means that A, C and F are siblings.

B > D > A/C/F

B - always the oldest, can be in only Group 1
A/C/F - All younger than D so they can be in Group 2 or Group 3 (depending on the age)
D can be in Group 1 or Group 2, but not in Group 3
E's position is unknown and can be in any group

Answer:
Group 2 but not Group 3: Daria
Any Group: Elise

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09 Jul 2026, 15:56

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We have A, B, C, D, E, F => 3 groups G1,G2,G3
Rules:
2 oldest in G1, 2 youngest in G3 and rest G2 | No same age | exactly 3 siblings

Lets check conditions.
1. B is older than D. B>D
2. D is older than 3 siblings, so D> all 3 siblings => B>D> 3 siblings.
3. E is not anyone of siblings. So basically B>D> [A,C,F](Siblings without known order)

Now if we can see E can be places anywhere since we have no connection or known age relating with any other member.

So Group 2 but not Group 3: Clearly Daria(D)
E>B>D>[ACF] or B>D>E>[ACF] or B>D>[ACF]>E
In all cases D can be in 1st and 2nd but not 3. B can only be in G1.

Any Group: Elise(E) .
As we can see above E can be a part of any group.

Bunuel

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09 Jul 2026, 17:10

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Bunuel

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09 Jul 2026, 19:36

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Let Anya, Bram, Clara, Daria, Elise, and Felix be denoted as A, B, C, D, E, and F, respectively. Oldest 1 and 2 as O1 and O2, Youngest 1 and 2 as Y1 and Y2, Remaining 1 and 2 as R1 and R2.

Step 1.

Set up groups (O1, O2) (R1, R2) (Y1, Y2)

Given

B>D

D> At least two other dubbed siblings

E is not a sibling

Implication is that F, A, C can be sibling denoted as S1 and S2

Step 2. Group 2 but not Group 3: D
D is the only one that can never be in group (Y1, Y2) as because at a minimum D is third youngest.

(O1, O2) (R1, D) (S1, S2)

Step 3. Any Group: E
Since F A C can be any of the two sibling, we don't know which one will be barred form Group Oldest at D maximum age (B,D) (Remaining) (Youngest)

Since we know E is not limited be being a sibling it can occupy any of the three groups

For this example Let A C be S1 and S2 but keep in mind F can be replaced for either.

(B,E)(F,D)(A,C), (B,D)(E,F)(A,C), (B,D)(F,A)(C,E)

Bunuel

A company is assigning 6 interns, , to 3 orientation groups based on age. The 2 oldest interns will be assigned to Group 1, the 2 youngest interns will be assigned to Group 3, and the remaining 2 interns will be assigned to Group 2. No two interns are the same age. Exactly 3 of the interns are siblings.

The following information is known:

• Bram is older than Daria.
• Daria is older than each of the 3 siblings.
• Elise is not one of the siblings.

Select for an intern who could be in Group 2 but could not be in Group 3, and select for an intern who could be in any one of the 3 groups. Make only two selections, one in each column.

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09 Jul 2026, 20:04

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This was a tricky one, Elise is the joker and can be in any group since we dont know her age, but, the interns that can potentially be in group 2 are any the siblings. I dont know for sure which specific one can't be in group 3 given the information provided, at least I can try mentioning any of them: Clara, Anya or Felix.

Bunuel

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09 Jul 2026, 20:37

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To solve this, first I tried to figure out who the siblings were. Daria is older than the siblings so she is out, Bram is older than Daria, so he also can't be a sibling, and Elise is stated to not be a sibling.

Then I wrote an inequality for the ages of the interns, but left of Elise because we don't have a reference point for her yet.

Bram>Daria>siblings

Daria has to be the 2nd or 3rd oldest because Bram is older than her and the three siblings are younger. We don't know if Elise is older or younger which would decide if Daria is 2 or 3. Daria can be in Group 1 or 2 but not 3

Since Bram is older than Daria, he is always in group 1 regardless of Elise's age.

The siblings Anya/Clara/Felix will be in positions 3-6. Since Bram and Daria are older than them that takes away position 1 and 2. If Elise is older than them that takes position 3 leaving 4-6 and if she is older that takes 6 leaving 3-5. In any scenario, the siblings are in Group 2 or 3, but not 1

Elise can be in in any position since she is not locked to an age. She could be older than all interns, younger, or in between any ages, so she can be in all groups.

The correct answer is Daria can be in Group 2 but not 3 and Elise can be in Any Group.

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09 Jul 2026, 20:51

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The siblings have to be Anya, Clara, and Felix which fixes the order as being Bram, then Daria, then the 3 siblings in some arrangement, leaving Elise floating anywhere. Daria is no lower than third (Group 1 or 2, never Group 3) and Elise is able slot in anywhere as oldest, middle, or the youngest.

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09 Jul 2026, 21:20

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A B C D E F
2 oldest - G1, 2 youngest - G3, rest - G2, 3 interns are siblings
Given B>D>S1...S2....S3....
Since E is not a sibling it can take any position - before D, after S3, after D --- so 'Any Group' is clearly Elise

For G2 not G3 we need to see who can be among the middle 2 folks (neither youngest nor oldest) but cannot be amongst the youngest
let's check B - the only person older than B can be E, meaning B will always be in G1
But if E is oldest, D can be in G2; Again, D cannot be in G3 since there are clearly atleast 3 folks younger than D, so D cannot be in the 'youngest' group

G2 not G3 - Daria
Any Group - Elise

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09 Jul 2026, 21:55

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Let us denote each name by their first letter A, B, C, D, E, F.
Groups:
1 -> Oldest
2 -> Middle
3 -> Youngest

Given info:
B>D
D>all three siblings
E is not one of the siblings

This tells us B, D, E are not part of the siblings, hence A, C, F are siblings.

As it stands, B>D>ACF (ACF can be in any order). E can be anywhere.

Group 2 but not Group 3:
B will always be Group 1, irrespective of where E lies.
D could be Group 2 if E is older than D or Group 1 if E is younger than D, but D can never be Group 3.
Thus, D.

Any Group:
E is the only one who can be in any group as we have no information about E's age.
Thus, E.

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09 Jul 2026, 22:52

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Given constraints - Group 1 will have the oldest 2 interns
Group 3 will have the youngest 2 interns
so the remaining will be in the middle in Group 2.

We have been given that 3 of the 6 people are siblings.

Information-
Bram is older than Daria
Daria is older than each of the 3 siblings
Based on this, we can easily deduce that a. Bram is not one of the siblings and also is older than 4 people - 3 siblings and Daria. b. Bram will have to be in Group 1.
Daria on the other hand can be either in Group 1 (if out of the 3 siblings, 2 are in the middle and 1 is the younger one) or in Group 2 (if out of the 3 siblings 2 are in youngest lot and 1 is in the middle). It is clear that Daria cannot be in Group 3.

Elise is not one of the siblings.
Since, Daria is a movable variable (group 1 or group 2), let's make scenarios.
If Daria is in group 1 and is elder than 3 siblings, then Elise can be either be in group 2 or in group 3 since Group 1 would already have Bram and Daria.
On the other hand, if Daria is in group 2 and he is older than 3 siblings, then, Elise will have to be in group 1.
So Elise can be in any of the groups.

So finally,
Daria can be in Group 2 but not 3 and Elise can be in any of the groups.

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09 Jul 2026, 23:27

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Given 6 interns are Anya, Bram, Clara, Daria, Elise, Felix

Group 1 = 2 oldest
Group 2 = middle 2
Group 3 = 2 youngest

Conditions given:
Bram is older than Daria.
Daria is older than each of the 3 siblings.
Elise is not one of the siblings.
Exactly 3 interns are siblings.

Since Elise is not a sibling, the only possible siblings are Anya, Clara, and Felix.

Daria is older than all 3 siblings

Bram is older than Daria:
Bram > Daria > Anya OR Clara OR Felix

Elise can be anywhere in the age order.
Possible groups
Bram: Group 1 only
Daria: Group 1 or Group 2
Anya: Group 2 or Group 3
Clara: Group 2 or Group 3
Felix: Group 2 or Group 3
Elise: Group 1, Group 2, or Group 3

Therefore:

Group 2 but not Group 3 = Daria
Any Group = Elise

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09 Jul 2026, 23:28

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We have,

Daria is older than each of 3 siblings, so daria is not the sibling
Bram is older than Daria, so Bram cannot not be one of the sibling
Elise is not a sibling.

Therefore, 3 siblings are

Anya, Clara, Felix

Age order will be

Bram > Daria> Anya, Clara, Felix

Groups:

Group 1 = 2 Oldest
Group 2 = 2 in the middle
Group 3 = 2 youngest

Group 2, by not group 3:

If Elise is younger than Daria, Daria will be in Group 1.
If Elise is older than Daria, then Daria will be in group 2.

Daria can never be in group 3 as 3 siblings are always younger than Daria.

Any group:

Elise can be in any of the group,

1. Group 1: If Elise is oldest
2. Group 2 : If Elise is younger than Daria & older than all the 3 sibling.
3. Group 3: If Elise is younger than the siblings

Answer:

Group 2 but not group 3 = Daria
Any Group = Elise

Bunuel

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09 Jul 2026, 23:35

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Let's consider age of people as following
A : Anya
B : Bram
C : Clara
D : Daria
E : Elise
F : Felix

As per the information given in the question stem,
B>D

D > (each of the siblings)
Elise is not one of the siblings. Hence, siblings are remaining people. i.e. A, C, and F.
That means B>D> ( A, C, F) . No data is available about E.

Since oldest two people are assigned to group 1 . B is definitely in Group 1 (whether E is older than B or not).
If E is older than B, E>B>D>(A,C,F), D is part of group 2.
If E is not older than B, B>D>(A, C, F , E), D is part of group 1.

Now, remaining people are A, C , F and E.
Out of these 4 people, 2 people have to be in group 1 and 2 people have to be in group 2. Since, no constraint is given for E. E could be in any group along with logic mentioned in above analysis.

Bunuel

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09 Jul 2026, 23:36

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Ans - Group 2 but not group 3 - Daria
Any group - Elise

sol
6 inters - A , B , C, D, E and F

Group 1 - 2 oldest interns
Group 2 - any one
Group 3 - 2 youngest interns

3 interns are siblings

B> D
D > 3 siblings

So B>D> 3 siblings
So D can be in group 2 but def not in group 3 as she is older than 3 people already so she cannot be in 2 youngest category

Elise is not one of the siblings , but this does not specify any age category so she can still be the oldest , youngest among the group so she can be in any group

Bunuel

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10 Jul 2026, 00:15

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A,B,C,D,E,F

we have 3 groups.
g-1 = 2 oldest.
g-2= remaining two people.
g-3= 2 youngest.

no two of same age.
three people are siblings.

constrains

elise is not among the siblings.
B>D
D > each 3 siblings.

since E is not among sibling and B> D that means A,C,F are siblings.

so means B>D>A,C,F
now E could be anywhere in this pattern.

so that means person who could be in any of three group could be E.

now since we know g-3 is for youngest and B>D. E can be older than D or not. and D is older than A,C,F. D cant be in g-3 at all.

so there we go that D can be ing g-2 but not in g-3

Bunuel

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10 Jul 2026, 00:31

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Bram > Daria
Daria > each of her 3 siblings. Which means Daria >=4
Daria cannot be in the group 3.

Elsie is mentioned is not Daria's Siblings. SO Elise can be younger than Daria + 3 siblings. Or Elise can be in between those three siblings or Elsie can older than Daria or Bram. So Elise can be in any group.

IMO: Group 2 but not 3: Daria.
Any Group is: Elise.

Bunuel

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10 Jul 2026, 00:48

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As per the question, lets make few cases,

we don't know the relationship of elsie with anyone so they can be anywhere and we know as per the question that Anya Clara and Felix has to be three siblings. Bram can't be because he or she are older than Daria and all three siblings are younger than Daria.

case 1
Elsie
Bram
Daria
Three siblings

Case 2
Bram
Elsie
Daria
Three siblings

Case 3
Bram
Daria
Elsie
3 siblings

Case 4
Bram
Daria
3 siblings
Elsie

Case 5
Bram
Daria
elsie in between 3 siblings

please note that Daria can never be in group 3 or last group or the one with youngest folk as he/she will always have at least 3 people beneath her.
so Daria could be in 2 but never be in 3

Considering Elsie's incomplete relation with anyone, he/she can be in any group. Case 1 and 2 first group, case 2 second group and case 4 third group

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10 Jul 2026, 00:51

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Bunuel

From the statements we have

(1) B E D _ _ _

or

(2) B D _ _ _ _ -- In this E can be in any of three dash

From (1) and (2) : We see that D can be in Group 2, but not in Group 3.

If its (1), then E is in group 1, and if its (2) then E can be in Group 2 or Group 3.

Group 2 but not in Group 3 : Daria
Any Group : Elise