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Bunuel
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Let no. of Men be x
So no. of women = 45-x

Using formula, Average= sum/no.of observation
For men,
65 = SUM 1 / x ---> Sum1 = 65x
For Women,
70= Sum2 / 45-X ---> Sum 2 = 70(45-x)
For total 45 students,
67 = Sum total / 45 ---> Sum total = 67x45

Now,
Sum total = Sum 1 + sum 2
So,
67x45 = 65x + 70(45-x) = 65x + 70x45 - 70x
=> 67x45 - 70x45 = 65x-70x
=> x = 27
Hence, A
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say total male = x
female = 45-x

total score for x male = 65x
total score for female = 70 (45-x)

now total average for both = 67
65x + 70 (45-x)/ 45 = 67
65x + 3150-70x = 3015

x= 27

choice A
Bunuel
A total of 45 male and female students took a math test. The male students have an average score of 65, and the female students have an average score of 70. If the overall average score for both male and female students is 67, how many male students participated in the test?

A. 27
B. 31
C. 33
D. 35
E. 37


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M+F= 45
F=45-M
Sum of Female scores = 70F
Sum of Male scores = 65M

Overall Average = 67
Sum of F+Sum of M = 67(M+F)
70F+65M= 67(45)
70(45-M)+65M = 3015
3150 -70M+65M = 3015
5M= 135
M= 27

A
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65 ---- 67 ----70

2 -------3

ratio is 3/5 of 45 = 27.

2/5 of 45 = 18

alligation mixture.


Bunuel
A total of 45 male and female students took a math test. The male students have an average score of 65, and the female students have an average score of 70. If the overall average score for both male and female students is 67, how many male students participated in the test?

A. 27
B. 31
C. 33
D. 35
E. 37


This is a PS Butler Question

Check the links to other Butler Projects:

­
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