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Hi,

I am not sure about the first part of the equation. Is the question (105-103)*0.00037?

In general, below is the way to solve such questions that have decimals that repeat indefinitely:

1000x = 0.3737
100000x = 37.3737


1000x = 0.3737
100000x - 1000x = 37.3737 - 0.3737
99000x = 37
x = 37/99000

Hope this is of use to you to solve the main question.

regards,
Jack
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are the answer choices correct here? i got 74/99000. how is the answer E? any explanations?
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Thanks Bunuel. Sorry for the mess up with the powers...
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Hi Bunuel, arent you supposed to do the parenthesis first? so \((10^5-10^3)\) becomes \(10^2=100*0.0003737\)..

where am I going wrong here? :oops:
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Another way to solve is by opening parenthesis and multiplying 0.00037 by 10^5 and then by 10^3. If you notice the fact that 0.00037*10^3 will get rid of repeating 37s, the problem boils down to just multiplying 0.00037 by 10^5
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Instead of 99000*0.000(37), I just did 100000*0.000(37) and got 37.(37), so the closest is E
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Hi Bunuel, arent you supposed to do the parenthesis first? so \((10^5-10^3)\) becomes \(10^2=100*0.0003737\)..

where am I going wrong here? :oops:

This is wrong. \(\frac{10^5}{10^3} = 10^2\)

As far as \(10^5 - 10^3\) is concerned, \(10^5\) is way high compared to \(10^3\)

So, \(10^5 - 10^3 \approx10^5\)
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aimingformba
If the digits 37 in the decimal 0.00037 repeat indefinitely, what is the value of (10^5-10^3)(0.00037)?

A. 0
B. 0.37 repeating
C. 3.7
D. 10
E. 37

Note : Rule to convert mixed recurring decimal to fraction : In the numerator write the entire given number formed by the (recurring and non - recurring parts) and subtract from it the part of the decimal that is not recurring. In the denominator, write as many nines as the number of digits recurring and then place next to it as many zeros as there are digits without recurring in the given decimal.

Converting the mixed recurring decimal (\(0.00037\)) [digits \(37\) repeat indefinitely] to fraction we get;

\(\frac{37-000}{99000} = \frac{37}{99000}\)

\((10^5-10^3)(0.00037)\)

\(10^3(10^2-1)(\frac{37}{99000})\)

\(10^3(100-1)(\frac{37}{99000})\)

\(\frac{1000 * 99 * 37}{99000} = 37\)

Answer (E)...
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We can just round it to 0.0004 and check the answer choices!
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aimingformba
If the digits 37 in the decimal 0.00037 repeat indefinitely, what is the value of (10^5-10^3)(0.00037)?

A. 0
B. 0.37 repeating
C. 3.7
D. 10
E. 37

Note that the answer options are very far apart so some approximation should have no impact.

10^5 is much greater than 10^3 so we can approximate (10^5-10^3) to be just 10^5

10^5 * .000373737 = approx 37.3737...

Answer (E)
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My approach is as follows:

\((10^5-10^3)(\frac{37}{99}*10^{-3})\)
\(\implies\) \(10^3(10^2-1)(\frac{37}{99}*10^{-3})\)
\(\implies\) \(10^3(10-1)(10+1)(\frac{37}{99}*10^{-3})\)
\(\implies\) \(10^3*37*10^{-3}\)
\(\implies\) \(10^0*37=37\)

Kudos are very much appreciated :)
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