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GMATGuruNY
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Train A traveling at 60 m/hr leaves New York for Dallas at 6 29 Mar 2020, 14:04
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Train A traveling at 60 m/hr leaves New York for Dallas at 6 P.M. Train B traveling at 90 m/hr also leaves New York for Dallas at 9 P.M. Train C leaves Dallas for New York at 9 P.M. If all three trains meet at the same time between New York and Dallas, what is the speed of Train C if the distance between Dallas and New York is 1260 miles?

A. 60 m/hr
B. 90 m/hr
C. 120 m/hr
D. 135 m/hr
E. 180 m/hr
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Since A leaves from NY 3 hours earlier than B leaves from NY, A's travel time is 3 hours greater than B's travel time.
Rate and time have a RECIPROCAL RELATIONSHIP.
The rate ratio for A and B = 60:90.
Thus:
The time ratio for A and B to meet = 90:60 = 9:6, with the result that A's time = 9 hours and B's time = 6 hours, for a difference of 3 hours.

Since B travels for 6 hours at 90 mph, the distance traveled by B = (rate)(time) = 90*6 = 540 miles.
For C to meet the other two trains, it must travel the remainder of the 1260-mile distance between NY and Dallas:
1260 - 540 = 720 miles.
Since C and B both leave at 9pm -- and B travels for 6 hours -- C's time must also be 6 hours.
Thus:
C's rate \(= \frac{distance}{time} = \frac{720}{6} = 120\) mph

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Train A traveling at 60 m/hr leaves New York for Dallas at 6 13 Oct 2025, 06:58
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