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maheshsrini
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maheshsrini
In the attached figure, AB=10, CD=40, Find EF?

This is not a complete question.
1. Is AB||CD||EF?
2. Are AEC and BED straight lines.

Even with above information, we will need something else to deduce the length of EF.

What is the source of the question?
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yeah we need BF, FC or the ratio
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fluke
maheshsrini
In the attached figure, AB=10, CD=40, Find EF?

This is not a complete question.
1. Is AB||CD||EF?
2. Are AEC and BED straight lines.

Even with above information, we will need something else to deduce the length of EF.

What is the source of the question?

Dear Fluke
considering AC & DB straight Lines
i got the answer EF = 8 by property of similar triangles

Explaination
let BF = x & FC = z & EF = y (which we need to find out)

from similar triangle properties
40/y=x+z/x ..........(1)
10/y=x+z/z............(2)
now with both the equation we have 40x=10z
so x/z=1/4
now with componendo rule of ratios we have
x+z/z=(1+4)/4= 5/4
now putting this back in eqn (2) we get y = 8 :o :o

please let me know the OA :? :?
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fluke
maheshsrini
In the attached figure, AB=10, CD=40, Find EF?

This is not a complete question.
1. Is AB||CD||EF?
2. Are AEC and BED straight lines.

Even with above information, we will need something else to deduce the length of EF.

What is the source of the question?

Dear Fluke
considering AC & DB straight Lines
i got the answer EF = 8 by property of similar triangles

Explaination
let BF = x & FC = z & EF = y (which we need to find out)

from similar triangle properties
40/y=x+z/x ..........(1)
10/y=x+z/z............(2)
now with both the equation we have 40x=10z
so x/z=1/4
now with componendo rule of ratios we have
x+z/z=(1+4)/4= 5/4
now putting this back in eqn (2) we get y = 8 :o :o

please let me know the OA :? :?

Correct. Good job.
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fluke

Correct. Good job.

Thank God It was correct...... :-D :-D
thanks for the kudos as well fluke :-D :-D :-D
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maheshsrini
In the attached figure, AB=10, CD=40, Find EF?

Good call Warlock007.
In my geometry class, I like to discuss a few common figures in which the concept of similar triangles jumps right out at you. Giving below some of them.
Attachment:
Ques2.jpg
Ques2.jpg [ 14.24 KiB | Viewed 2852 times ]

See if you can figure out the similar triangles and the reason they are similar in each one of these cases. (Angles that look 90 are 90 here). Most of them have right triangles/lines parallel to a side of the triangle.
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VeritasPrepKarishma
maheshsrini
In the attached figure, AB=10, CD=40, Find EF?

Good call Warlock007.
In my geometry class, I like to discuss a few common figures in which the concept of similar triangles jumps right out at you. Giving below some of them.
Attachment:
Ques2.jpg

See if you can figure out the similar triangles and the reason they are similar in each one of these cases. (Angles that look 90 are 90 here). Most of them have right triangles/lines parallel to a side of the triangle.

Hey thanks karishma
i deserve a kudos from you then.......... :-D :-D
thanks for the figures
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10/BC=EF/FC
40/BC=EF/BF

Solving, I got EF=8.
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I got 8 using the similar triangles concept..
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good explanation Warlock007 and thanks for the diagrams Karishma...(need to attend your veritas class :)
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puneetj
good explanation Warlock007 and thanks for the diagrams Karishma...(need to attend your veritas class :)

Hey Puneet
what are you waiting for man
give me kudos.......... :beer :beer
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from similar triangle properties
40/y=x+z/x ..........(1)
10/y=x+z/z............(2)

How do we get this equation? which property of similar triangle is this?
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sudhir18n
from similar triangle properties
40/y=x+z/x ..........(1)
10/y=x+z/z............(2)

How do we get this equation? which property of similar triangle is this?

this is about the ratios of the sides
refer to what karishma has explained in her previous post
or refer to bunuel or to OG theory even
that will help you to understand this better

hope this helps :) :)
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Warlock007
puneetj
good explanation Warlock007 and thanks for the diagrams Karishma...(need to attend your veritas class :)

Hey Puneet
what are you waiting for man
give me kudos.......... :beer :beer


Ok Warlock............but don't forget to give it back someday :-D
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puneetj
Warlock007
puneetj
good explanation Warlock007 and thanks for the diagrams Karishma...(need to attend your veritas class :)

Hey Puneet
what are you waiting for man
give me kudos.......... :beer :beer


Ok Warlock............but don't forget to give it back someday :-D

Sure man
i never get stingy when it comes for kudos.... :cool :gl
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using similar triangle
EF/AB = CF/BC
EF/CD = BF/BC

4EF = 40-EF thus EF = 8



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