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Triangle ABC has AB = 2*AC. Let D and E be on AB and BC, respectively,

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Joined: 02 Sep 2009
Posts: 54375
Triangle ABC has AB = 2*AC. Let D and E be on AB and BC, respectively,  [#permalink]

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29 Mar 2019, 02:04
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Difficulty:

55% (hard)

Question Stats:

50% (03:42) correct 50% (03:48) wrong based on 8 sessions

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Triangle ABC has AB = 2*AC. Let D and E be on AB and BC, respectively, such that angle BAE = angle ACD. Let F be the intersection of segments AE and CD, and suppose that triangle CFE is equilateral. What is angle ACB?

(A) 60°
(B) 75°
(C) 90°
(D) 105°
(E) 120°

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Re: Triangle ABC has AB = 2*AC. Let D and E be on AB and BC, respectively,  [#permalink]

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29 Mar 2019, 08:21
Bunuel wrote:
Triangle ABC has AB = 2*AC. Let D and E be on AB and BC, respectively, such that angle BAE = angle ACD. Let F be the intersection of segments AE and CD, and suppose that triangle CFE is equilateral. What is angle ACB?

(A) 60°
(B) 75°
(C) 90°
(D) 105°
(E) 120°

draw fig as per given info
we shall get angle BAE= 30 = angle ACD
and angle FCE= 60
so angle ACB = 90
IMO C
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Re: Triangle ABC has AB = 2*AC. Let D and E be on AB and BC, respectively,   [#permalink] 29 Mar 2019, 08:21
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