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KarishmaB
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Truck A is on a straight highway heading due south at the same time Truck B is on a different straight highway heading due east. At 1:00 PM, Truck A is exactly 14 miles north of Truck B. If both trucks are traveling at a constant speed of 30 miles per hour, at which of the following times will they be exactly 10 miles apart?

A. 1:10 PM
B. 1:12 PM
C. 1:14 PM
D. 1:15 PM
E. 1:20 PM

Quickly draw to understand what the question is telling you. The first diagram shown you the situation at 1:00 pm. The second diagram shows the pic of some time later:
Attachment:
Ques3.jpg

The hypotenuse of 10 should remind you of the 3-4-5 pythagorean triplet. Here we might have its multiple 6-8-10.
So we are looking at the vertical distance of 8 (which means truck A has traveled a distance of 6 miles from the 14 miles) and horizontal distance of 6 traveled by truck B - both trucks traveled 6 miles in this case which is expected since their speed is the same.
They travel 30 miles in one hour (60 mins) so they will travel 6 miles in 60*6/30 = 12 mins.

Answer (B)
Great tip regarding right angle triplet. I saw similar question for minimum distance where we have to form quadratic equation and find -b/2a. My dumb self did the same thing here too and wasted time.
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