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bschool83
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Truck X is 13 miles ahead of Truck Y, which is traveling the same dire Updated on: 16 Jan 2017, 03:10
Originally posted by bschool83 on 12 Aug 2011, 15:28.
Last edited by Bunuel on 16 Jan 2017, 03:10, edited 1 time in total.
Renamed the topic and edited the question.
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Truck X is 13 miles ahead of Truck Y, which is traveling the same direction along the same route as Truck X. If Truck X is traveling at an average speed of 47 miles per hour and Truck Y is traveling at an average speed of 53 miles per hour, how long will it take Truck Y to overtake and drive 5 miles ahead of Truck X?

A. 2 hours
B. 2 hours 20 minutes
C. 2 hours 30 minutes
D. 2 hours 45 minutes
E. 3 hours
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Truck X is 13 miles ahead of Truck Y, which is traveling the same dire 12 Aug 2011, 19:58
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Relative speed of Truck Y (wrt speed of X) = 53-47 = 6
Distance Truck Y needs to travel = 13 (distance between X and Y) + 5 (To go 5 miles ahead of X) = 18

So time required = 18/6 = 3 Hours
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Truck X is 13 miles ahead of Truck Y, which is traveling the same dire 12 Aug 2011, 17:52
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bschool83
Track X is 13 miles ahead of Truck Y, which is travelling the same direction along the same route as Truck X. If Truck X is traveling at an average speed of 47 miles per hour and Truck Y is traveling at an average speed of 53 miles per hour, how long will it take Truck Y to overtake and drive 5 miles ahead of Truck X?
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Let the time taken by truck Y to overtake truck X by 5 kms be Z hrs. Now according to question, truck Y is 13 miles behind truck x and after Z hrs it overtakes truck truck X by 5 miles. so in z hrs truck Y will have traveled 18 miles more than truck x. so,

47Z +18 = 53Z

18 =6Z , thus Z = 3 hrs.

so truck Y will take 3 hrs to overtake truck X by 5 miles.
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Truck X is 13 miles ahead of Truck Y, which is traveling the same dire 13 Aug 2011, 07:28
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For those who want to learn a more strategic way to solve such problems:

If two objects start moving towards each other in straight line at the same time, their speeds add up. If moving away, subtract their speeds.

Therefore at a given time, X and Y are 13 + 5 = 18 miles apart. Their speeds relative to each other is 53 - 47 = 6mph.
Therefore, they meet in 18/6 hrs = 3 hours.
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Truck X is 13 miles ahead of Truck Y, which is traveling the same dire 13 Aug 2011, 12:28
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Hi guys, is this a 700 level question?!?! i'm asking it because i've started studying the quantitative section a few days ago but it seams not that tough ah? thanks
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Truck X is 13 miles ahead of Truck Y, which is traveling the same dire 14 Aug 2011, 10:18
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well, in ''overtake'' problems u need to subtract one speed from another one. to overcome X, Y needs to ride 13+5 miles. so (53-47)t=13+5 6t=18 t=3 h
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Truck X is 13 miles ahead of Truck Y, which is traveling the same dire 14 Aug 2011, 10:55
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Relative speed = 6 mph => Y gains 6 miles every hour.

Y needs to travel 18 miles more than X. => Y needs to gain 18 miles.

from the above two statements we can say that it will take 3 hours for Truck Y to overtake and drive 5 miles ahead of Truck X.

Answer 3 hours.
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Truck X is 13 miles ahead of Truck Y, which is traveling the same dire 28 Dec 2015, 03:19
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Truck X is 13 miles ahead of Truck Y, which is traveling the same direction along the same route as Truck X. If Truck X is traveling at an average speed of 47 miles per hour and Truck Y is traveling at an average speed of 53 miles per hour, how long will it take Truck Y to overtake and drive 5 miles ahead of Truck X?

Relative speed = 53-47 = 6 miles per hour
Dist required = 13+5 = 18 miles
Time taken to overtake = 18/6 = 3 hours. E is the answer.
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Truck X is 13 miles ahead of Truck Y, which is traveling the same dire 18 Jan 2017, 11:04
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bschool83
Truck X is 13 miles ahead of Truck Y, which is traveling the same direction along the same route as Truck X. If Truck X is traveling at an average speed of 47 miles per hour and Truck Y is traveling at an average speed of 53 miles per hour, how long will it take Truck Y to overtake and drive 5 miles ahead of Truck X?

A. 2 hours
B. 2 hours 20 minutes
C. 2 hours 30 minutes
D. 2 hours 45 minutes
E. 3 hours
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We have a catch-up-and-pass problem, for which we can use the formula:

change in distance/change in rate = catch-up-and-pass time

We are given that Truck X is 13 miles ahead of Truck Y, and we need to determine the time it takes Truck Y to overtake Truck X by 5 miles. Thus, the change in distance is 13 + 5 = 18 miles.

We are also given that Truck X travels at a constant speed of 47 mph and Truck Y at a speed of 53 miles per hour. Thus, the change in rate is 53 - 47 = 6 mph.

Therefore, the catch-up-and-pass time is: 18/6 = 3 hours.

Answer: E
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Truck X is 13 miles ahead of Truck Y, which is traveling the same dire 09 Oct 2024, 21:00
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bschool83
Truck X is 13 miles ahead of Truck Y, which is traveling the same direction along the same route as Truck X. If Truck X is traveling at an average speed of 47 miles per hour and Truck Y is traveling at an average speed of 53 miles per hour, how long will it take Truck Y to overtake and drive 5 miles ahead of Truck X?

A. 2 hours
B. 2 hours 20 minutes
C. 2 hours 30 minutes
D. 2 hours 45 minutes
E. 3 hours
Show more
Right now, Truck Y is 13 Miles behind. It needs to be 5 Miles ahead. So it needs to cover a relative distance of 13 + 5 = 18 Miles.

Time taken = Relative distance/Relative Speed = 18/(53 - 47) = 18/6 Hours = 3 Hours.


Answer is option E
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Truck X is 13 miles ahead of Truck Y, which is traveling the same dire 19 Apr 2026, 12:02
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