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02 Aug 2021, 04:15
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
86% (01:59) correct
14%
(02:20)
wrong
based on 50
sessions
History
Date
Time
Result
Not Attempted Yet
Twenty times a positive integer is less than its square by 96. What is the integer?
(A) 20
(B) 24
(C) 30
(D) 32
(E) 35
(A) 20
(B) 24
(C) 30
(D) 32
(E) 35
02 Aug 2021, 04:26
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Let's assume the integer is x
x^2 - 20x = 96
it's a quadratic equation
(x-24)(x+4) = 0
After solving, x = 24 & -4
Since x is a positive integer, we will take x = 24
OA: B
x^2 - 20x = 96
it's a quadratic equation
(x-24)(x+4) = 0
After solving, x = 24 & -4
Since x is a positive integer, we will take x = 24
OA: B
02 Aug 2021, 04:27
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Explanation:
Method 1:
20*x = x^2 - 96
x^2 - 20x - 96 = 0
x^2 + 4x - 24x - 96 = 0
x(x+4) - 24(x+4) = 0
(x-24)(x+4) = 0
x = 24, -4
Method 2:
x^2 - 20x - 96 = 0
put value from options and check which one satisfies it.
IMO-B
Method 1:
20*x = x^2 - 96
x^2 - 20x - 96 = 0
x^2 + 4x - 24x - 96 = 0
x(x+4) - 24(x+4) = 0
(x-24)(x+4) = 0
x = 24, -4
Method 2:
x^2 - 20x - 96 = 0
put value from options and check which one satisfies it.
IMO-B
