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Two containers contain milk and water solutions of volume x liters and

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Intern
Intern
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Joined: 30 Sep 2017
Posts: 36
Location: India
Concentration: Entrepreneurship, General Management
Schools: IIM Udaipur '17
GMAT 1: 700 Q50 V37
GPA: 3.7
WE: Engineering (Energy and Utilities)
Two containers contain milk and water solutions of volume x liters and [#permalink]

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New post 08 Dec 2017, 06:35
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Difficulty:

  75% (hard)

Question Stats:

58% (01:39) correct 43% (02:03) wrong based on 40 sessions

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Two containers contain milk and water solutions of volume x liters and y liters, respectively. What would be the minimum concentration of milk in either container so that when the entire contents of both containers are mixed, 30 liters of 80 percent milk solution is obtained?

(1) x = 2y
(2) x = y +10
[Reveal] Spoiler: OA

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Two containers contain milk and water solutions of volume x liters and [#permalink]

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New post 08 Dec 2017, 07:03
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My understanding is that we are being asked what is the minimum concentration of milk in either X or Y in order to achieve a 30-liters mixture of 80% milk and 20% water when both X and Y are combined.

Elaborating the question stem, we get:
30liters -> 24 milk, 6 water.

By doing some quick math with X+Y=30 and the two answer options, we easily find out that they basically tell us the same thing, i.e. X=20, Y=10. We can therefore boil down our answers to either D) or E).

We now need to find the scenario in which the milk concentration in either X or Y is lowest. Since our "target" milk amount is 24, every percentage point of concentration in X yields a higher amount of milk, therefore we can assume that X has a 100% concentration of milk, leaving us with 20 liters of milk out of the 24 we need. Finally, we proceed to fill in the remaining 4 liters with Y, with a concentration of 4/10=40%.

Answer D)
Two containers contain milk and water solutions of volume x liters and   [#permalink] 08 Dec 2017, 07:03
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Two containers contain milk and water solutions of volume x liters and

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