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Two cylindrical candles of the same height and diameter burn at the sa

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Two cylindrical candles of the same height and diameter burn at the sa  [#permalink]

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New post 06 Dec 2017, 22:17
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Two cylindrical candles of the same height and diameter burn at the same uniform rate. Each takes 4 hours to be consumed. If the first candle is lit at 8.00 p.m and the second at 9.00 p.m, at what time will the second candle be exactly 3 times as tall as the first?

(A) 9.30 p.m
(B) 10.00 p.m
(C) 10.30 p.m
(D) 11.00 p.m
(E) 11.30 p.m

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Re: Two cylindrical candles of the same height and diameter burn at the sa  [#permalink]

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New post 06 Dec 2017, 23:08
Going by options, at 11.30 , candle 1 will be 1/8th of length, candle 2 will be 3/8 of length. Option E

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Re: Two cylindrical candles of the same height and diameter burn at the sa  [#permalink]

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New post 07 Dec 2017, 00:39
Bunuel wrote:
Two cylindrical candles of the same height and diameter burn at the same uniform rate. Each takes 4 hours to be consumed. If the first candle is lit at 8.00 p.m and the second at 9.00 p.m, at what time will the second candle be exactly 3 times as tall as the first?

(A) 9.30 p.m
(B) 10.00 p.m
(C) 10.30 p.m
(D) 11.00 p.m
(E) 11.30 p.m

Assume both the candles be of height 40 cm and their burn rate be 10 cm/ hr

9:00 PM (Candle Left) A 30 Cm B 40 Cm
10:00 PM (Candle Left) A 20 Cm B 30 Cm
11:00 PM (Candle Left) A 10 Cm B 20 Cm
11:30 PM (Candle Left) A 5 Cm B 15 Cm
E
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Two cylindrical candles of the same height and diameter burn at the sa  [#permalink]

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New post 07 Dec 2017, 05:13
Bunuel wrote:
Two cylindrical candles of the same height and diameter burn at the same uniform rate. Each takes 4 hours to be consumed. If the first candle is lit at 8.00 p.m and the second at 9.00 p.m, at what time will the second candle be exactly 3 times as tall as the first?

(A) 9.30 p.m
(B) 10.00 p.m
(C) 10.30 p.m
(D) 11.00 p.m
(E) 11.30 p.m


Let the two candles are of 40 cm each
At 9 pm C1 = 3/4(40) = 30 cm and C2 = 40 cm

Let x and y be the length of candle that needs to be consumed from C1 and C2 respectively for the second candle to be exactly 3 times as tall as the first.
40-x = 3(30-y)
Since both the candles length are considered at 9 pm and are getting consumed at same rate, x= y
y= 25

fraction of candle 2 left : 25/40 = 5/8
1 candle gets consumed in 4 hrs,
time taken for 5/8 candle to consume = 4*(5/8) = 2.5 hrs

time = 9pm +2.5 hrs = 11.30 pm
--E--
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Two cylindrical candles of the same height and diameter burn at the sa &nbs [#permalink] 07 Dec 2017, 05:13
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