GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 23 Sep 2018, 15:03

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Two different teams, X and Y, which have no members in

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Director
Director
User avatar
Joined: 07 Jun 2004
Posts: 604
Location: PA
Two different teams, X and Y, which have no members in  [#permalink]

Show Tags

New post 22 Mar 2011, 06:55
1
4
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

74% (00:47) correct 26% (01:22) wrong based on 127 sessions

HideShow timer Statistics

Two different teams, X and Y, which have no members in common, will merge to form a new team. If the average (arithmetic mean) height of the players on team X is 5 feet 7 inches and the average height of the players on team Y is 5 feet 10 inches, which team has more players?

(1) If a new team, team Z, is formed from teams X and Y it will have an average height of 5 feet 9 inches.
(2) There are 12 players on team X.

_________________

If the Q jogged your mind do Kudos me : )

Retired Moderator
avatar
B
Joined: 16 Nov 2010
Posts: 1451
Location: United States (IN)
Concentration: Strategy, Technology
Premium Member Reviews Badge
Re: average ds  [#permalink]

Show Tags

New post 22 Mar 2011, 07:04
The answer is A.

(1) gives us how a weighed average, that can be derived from the height of players in X and Y teams, is nearer to Y, so Y has more players.

(2) does not give any information about number of players in team Y, so not sufficient.
_________________

Formula of Life -> Achievement/Potential = k * Happiness (where k is a constant)

GMAT Club Premium Membership - big benefits and savings

Senior Manager
Senior Manager
avatar
G
Joined: 02 Apr 2014
Posts: 477
GMAT 1: 700 Q50 V34
Two different teams, X and Y, which have no members in  [#permalink]

Show Tags

New post 25 Oct 2017, 12:43
1
Hi the answer is A.

But i have a question, though it may look silly.

See, statement 1 says team z is formed from team X and team Y, but it is never mentioned that all players of team X and team Y will be included in team Z.
Please note new team (formed out of merge) given in the question and team Z mentioned in statement 1 may be different.

Say only 1 out of 100 players from team X and 24 out of 25 players from Y are included in Z, then, weighted average will be definitely towards the average of Y, proving Y has more players, but actually X has more players.

Confused !

Please help.
DS Forum Moderator
avatar
P
Joined: 22 Aug 2013
Posts: 1343
Location: India
Premium Member
Re: Two different teams, X and Y, which have no members in  [#permalink]

Show Tags

New post 26 Nov 2017, 00:33
hellosanthosh2k2 wrote:
Hi the answer is A.

But i have a question, though it may look silly.

See, statement 1 says team z is formed from team X and team Y, but it is never mentioned that all players of team X and team Y will be included in team Z.
Please note new team (formed out of merge) given in the question and team Z mentioned in statement 1 may be different.

Say only 1 out of 100 players from team X and 24 out of 25 players from Y are included in Z, then, weighted average will be definitely towards the average of Y, proving Y has more players, but actually X has more players.

Confused !

Please help.


Hi Santhosh

When nothing else is mentioned, I think its quite safe to assume that all members will merge. Though I believe actual GMAT will take utmost care of such things, as a question is revised and approved after many interventions by qualified people (I believe). Still when not mentioned, I think we can take this assumption.
Intern
Intern
avatar
B
Joined: 26 Sep 2017
Posts: 14
Re: Two different teams, X and Y, which have no members in  [#permalink]

Show Tags

New post 28 Feb 2018, 00:47
rxs0005 wrote:
Two different teams, X and Y, which have no members in common, will merge to form a new team. If the average (arithmetic mean) height of the players on team X is 5 feet 7 inches and the average height of the players on team Y is 5 feet 10 inches, which team has more players?

(1) If a new team, team Z, is formed from teams X and Y it will have an average height of 5 feet 9 inches.
(2) There are 12 players on team X.


Hi,
Can anybody explain me how to calculate answer 1?
Thanks
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 49320
Re: Two different teams, X and Y, which have no members in  [#permalink]

Show Tags

New post 28 Feb 2018, 01:00
lor12345 wrote:
rxs0005 wrote:
Two different teams, X and Y, which have no members in common, will merge to form a new team. If the average (arithmetic mean) height of the players on team X is 5 feet 7 inches and the average height of the players on team Y is 5 feet 10 inches, which team has more players?

(1) If a new team, team Z, is formed from teams X and Y it will have an average height of 5 feet 9 inches.
(2) There are 12 players on team X.


Hi,
Can anybody explain me how to calculate answer 1?
Thanks


Two different teams, X and Y, which have no members in common, will merge to form a new team. If the average (arithmetic mean) height of the players on team X is 5 feet 7 inches and the average height of the players on team Y is 5 feet 10 inches, which team has more players?

The average (arithmetic mean) height of the players on team X = 5 feet 7 = 67 inches;
The average (arithmetic mean) height of the players on team Y = 5 feet 10 inches = 70 inches.

(1) If a new team, team Z, is formed from teams X and Y it will have an average height of 5 feet 9 inches (69 inches). Since the overall average is closer to the average of team Y than it is to the average of team X, then team Y must have more members than team X. Sufficient.

Algebraically: \(69 =\frac{67x + 70y}{x + y}\). After simplifying we'll get 2x = y. Hecen, y > x.

(2) There are 12 players on team X. Clearly insufficient.

Answer: A.

Hope it's clear.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Intern
Intern
avatar
B
Joined: 20 Dec 2017
Posts: 34
CAT Tests
Two different teams, X and Y, which have no members in  [#permalink]

Show Tags

New post 28 Feb 2018, 01:08
lor12345 wrote:
rxs0005 wrote:
Two different teams, X and Y, which have no members in common, will merge to form a new team. If the average (arithmetic mean) height of the players on team X is 5 feet 7 inches and the average height of the players on team Y is 5 feet 10 inches, which team has more players?

(1) If a new team, team Z, is formed from teams X and Y it will have an average height of 5 feet 9 inches.
(2) There are 12 players on team X.


Hi,
Can anybody explain me how to calculate answer 1?
Thanks


Ignore the 5ft and only look at the inches to save time (since both have 5 fts).

Team X = 7 inch Avg
Team Y = 10 inch Avg
Team Z = 9 inch Avg

From here you can already guess that team Y has more players than X (Seeing that the combined Team Z has an average skewed closer to Team Y).

But if you want to calculate the exact ratio (which is not needed for this question:

\(\frac{Y-Z}{Z-X} = \frac{10-9}{9-7} = \frac{1}{2}\)

Team Y has twice as many players than team X.

Hopes this helps :-)
GMAT Club Bot
Two different teams, X and Y, which have no members in &nbs [#permalink] 28 Feb 2018, 01:08
Display posts from previous: Sort by

Two different teams, X and Y, which have no members in

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  

Events & Promotions

PREV
NEXT


Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.