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Two different teams, X and Y, which have no members in

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Two different teams, X and Y, which have no members in [#permalink]

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New post 22 Mar 2011, 05:55
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Question Stats:

76% (00:47) correct 24% (01:46) wrong based on 66 sessions

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Two different teams, X and Y, which have no members in common, will merge to form a new team. If the average (arithmetic mean) height of the players on team X is 5 feet 7 inches and the average height of the players on team Y is 5 feet 10 inches, which team has more players?

(1) If a new team, team Z, is formed from teams X and Y it will have an average height of 5 feet 9 inches.
(2) There are 12 players on team X.
[Reveal] Spoiler: OA

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Re: average ds [#permalink]

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New post 22 Mar 2011, 06:04
The answer is A.

(1) gives us how a weighed average, that can be derived from the height of players in X and Y teams, is nearer to Y, so Y has more players.

(2) does not give any information about number of players in team Y, so not sufficient.
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Two different teams, X and Y, which have no members in [#permalink]

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New post 25 Oct 2017, 11:43
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Hi the answer is A.

But i have a question, though it may look silly.

See, statement 1 says team z is formed from team X and team Y, but it is never mentioned that all players of team X and team Y will be included in team Z.
Please note new team (formed out of merge) given in the question and team Z mentioned in statement 1 may be different.

Say only 1 out of 100 players from team X and 24 out of 25 players from Y are included in Z, then, weighted average will be definitely towards the average of Y, proving Y has more players, but actually X has more players.

Confused !

Please help.
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Re: Two different teams, X and Y, which have no members in [#permalink]

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New post 25 Nov 2017, 23:33
hellosanthosh2k2 wrote:
Hi the answer is A.

But i have a question, though it may look silly.

See, statement 1 says team z is formed from team X and team Y, but it is never mentioned that all players of team X and team Y will be included in team Z.
Please note new team (formed out of merge) given in the question and team Z mentioned in statement 1 may be different.

Say only 1 out of 100 players from team X and 24 out of 25 players from Y are included in Z, then, weighted average will be definitely towards the average of Y, proving Y has more players, but actually X has more players.

Confused !

Please help.


Hi Santhosh

When nothing else is mentioned, I think its quite safe to assume that all members will merge. Though I believe actual GMAT will take utmost care of such things, as a question is revised and approved after many interventions by qualified people (I believe). Still when not mentioned, I think we can take this assumption.
Re: Two different teams, X and Y, which have no members in   [#permalink] 25 Nov 2017, 23:33
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Two different teams, X and Y, which have no members in

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